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love history [14]
3 years ago
7

A homeowner consumes 260 kWh of energy in July when the family is on vacation most of the time. Determine the average cost per k

Wh for the month using the following residential rate schedule: Base monthly charge of $10.00. First 100 kWh per month at 16 cents/kWh. Next 200 kWh per month at 10 cents/kWh. Over 300 kWh per month at 6 cents/kWh.
Engineering
1 answer:
Llana [10]3 years ago
7 0

Answer:

16.2 cents

Explanation:

Given that a homeowner consumes 260 kWh of energy in July when the family is on vacation most of the time.

Where Base monthly charge of $10.00. First 100 kWh per month at 16 cents/kWh. Next 200 kWh per month at 10 cents/kWh. Over 300 kWh per month at 6 cents/kWh.

For the first 100 kWh:

16 cent × 100 = 1600 cents = 16 dollars

Since 1 dollar = 100 cents

For the remaining energy:

260 - 100 = 160 kwh

10 cents × 160 = 1600 cents = 16 dollars

The total cost = 10 + 16 + 16 = 42 dollars

Note that the base monthly of 10 dollars is added.

The cost of 260 kWh of energy consumption in July is 42 dollars

To determine the average cost per kWh for the month of July, divide the total cost by the total energy consumed.

That is, 42 / 260 = 0.1615 dollars

Convert it to cents by multiplying the result by 100.

0.1615 × 100 = 16.15 cents

Approximately 16.2 cents

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2 years ago
Race car is accelerating and has a velocity of 10 m/s @ t=0. It completes a lap on a circular track of 400 m in 14 seconds. Calc
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Answer:

component of acceleration are a = 3.37 m/s² and ar = 22.74 m/s²

magnitude of acceleration is  22.98 m/s²

Explanation:

given data

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distance s = 400 m

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components and magnitude of acceleration after the car has travelled 200 m

solution

first we find the radius of circular track that is

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400 = 2πR

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and tangential acceleration is

S = ut + 0.5 ×at²

here u is initial speed and t is time and S is distance

400 = 10 × 14  + 0.5 ×a (14)²

a = 3.37 m/s²

and here tangential acceleration is constant

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v² = 10² + 2 ( 3.37) 200

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so radial acceleration at distance 200 m

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2 years ago
How do we find percentage error in measuring voltage across a resistor​
Black_prince [1.1K]

Answer:

  use the percentage error relation

Explanation:

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__

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