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notsponge [240]
3 years ago
7

The cost, C C, of producing x x Totally Cool Coolers is modeled by the equation C = 0.005 x 2 − 0.25 x + 12 C=0.005x2-0.25x+12 H

ow many coolers need to be produced and sold in order to minimize the cost? (Round to the nearest whole number.)
Chemistry
1 answer:
neonofarm [45]3 years ago
3 0

Answer:

25 coolers are need to be produce and sell in order to minimize the cost.

Explanation:

C = 0.005x^2-0.25x+12 ..[1]

Differentiating the given expression with respect to dx.

\frac{dC}{dx}=\frac{d(0.005x^2-0.25x+12)}{dx}

\frac{dC}{dx}=0.01x-0.25+0

Putting ,\frac{dC}{dx}=0

0=0.01x-0.25+0

0.01x=0.25

x = 25

Taking second derivative of expression [1]

\frac{d^2C}{dx^2}=\frac{d(0.01x-0.25)}{dx}=0.01

\frac{d^2C}{dx^2}>0 (minima)

25 coolers are need to be produce and sell in order to minimize the cost.

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6.47 M (3 s.f.)

Explanation:

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Average Molarity for HCl is .391
Ira Lisetskai [31]

Answer:

#1: 0.00144 mmolHCl/mg Sample

#2: 0.00155 mmolHCl/mg Sample

#3: 0.00153 mmolHCl/mg Sample

Explanation:

A antiacid (weak base) will react with the HCl thus:

Antiacid + HCl → Water + Salt.

In the titration of antiacid, the strong acid (HCl)  is added in excess, and you're titrating with NaOH moles of HCl that doesn't react.

Moles that react are the difference between mmoles of HCl - mmoles NaOH added (mmoles are Molarity×mL added). Thus:

Trial 1: 0.391M×14.00mL - 0.0962M×34.26mL = 2.178 mmoles HCl

Trial 2: 0.391M×14.00mL - 0.0962M×33.48mL = 2.253 mmoles HCl

Trial 3: 0.391M×14.00mL - 0.0962M×33.84mL = 2.219 mmoles HCl

The mass of tablet in mg in the 3 experiments is 1515mg, 1452mg and 1443mg.

Thus, mmoles HCl /mg OF SAMPLE<em> </em>for each trial is:

#1: 2.178mmol / 1515mg

#2: 2.253mmol / 1452mg

#3: 2.219mmol / 1443mg

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8 0
3 years ago
Select all that apply.
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4 years ago
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4 years ago
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A chemist working for Udensi industries wants to create a new ink for tattoos and cosmetics. Determine the theoretical yield of
leva [86]

Answer:

35.36 g

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

8Fe + S₈ —> 8FeS

Next, we shall determine the mass of Fe that reacted and the mass of FeS produced from the balanced equation. This can be obtained as follow:

Molar mass of Fe = 56 g/mol

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SUMMARY:

From the balanced equation above,

448 g of Fe reacted to produce 704 g of FeS.

Finally, we shall determine the theoretical yield of FeS as follow:

From the balanced equation above,

448 g of Fe reacted to produce 704 g of FeS.

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Thus, the theoretical yield of FeS is 35.36 g

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3 years ago
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