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fomenos
3 years ago
8

Help please correct answer i will mark brainliest​

Physics
1 answer:
murzikaleks [220]3 years ago
6 0

Answer:

19.21ms-¹

Explanation:

that is the solution above

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A raging bull of mass 700kg runs at 10 m/s. How much kinetic energy does it have?
Illusion [34]

Answer: 35000 J or 35kJ

Explanation:

Use equation for kinetic energy : Ek=mV²/2

m=700 kg

V=10m/s

-------------------

Ek= 700kg*100m²7s²/2

Ek=35000 J=35kJ

6 0
4 years ago
There are 1000 blank in a meter
Andru [333]

Answer:

1000 millimeters

Explanation:

5 0
3 years ago
A car drives 40km West, and then 160km North. What is the displacement of the car?
Galina-37 [17]

Answer: 1

Explanation:

8 0
3 years ago
Read 2 more answers
A common way to measure the distance to lightning is to start counting, one count per second, as soon as you see the flash. Stop
AURORKA [14]

Answer:

d = 1.07 mile

Explanation:

The rationale for this method is that the speed of light is much greater than the speed of sound, the definition of speed in uniform motion is  

v = d / t  

d = v t  

the speed of sound is worth  

v = 343 m / s  

Therefore, the speed of sound must be multiplied by time to do this, all the units must be in the same system, as the distance in miles is requested  

v = 343 m/s (1mile/1609 m) (3600s/1 h) = 343 (2.24) = 767.4 mile/h  

v = 343 m / s (1 mile / 1609 m) = 0.213, mile/ s  

If the measured time is t = 5s we multiply it by the speed  

we substitute  

d = 0.213 5

d = 1.07 mile

If you want to calculate the speed, this method in general is not widely used, since you must know the distance where the lightning occurred, which is relatively complicated.

8 0
3 years ago
Positive Charge is distributed along the entire x axis with a uniform density 12 nC/m. A proton is placed at a position of 1.00
lions [1.4K]

Answer:

b.  \Delta KE = 390 eV

Explanation:

As we know that the electric field due to infinite line charge is given as

E =\frac{\lambda}{2\pi \epsilon_0 r}

here we can find potential difference between two points using the relation

\Delta V = \int E.dr

now we have

\Delta V = \int(\frac{\lambda}{2\pi \epsilon_0 r}).dr

now we have

\Delta V = \frac{\lambda}{2\pi \epsilon_0}ln(\frac{r_2}{r_1})

now plug in all values in it

\Delta V = \frac{12\times 10^{-9}}{2\pi \epsilon_0}ln(\frac{1+5}{1})

\Delta V = 216ln6 = 387 V

now we know by energy conservation

\Delta KE = q\Delta V

\Delta KE = (e)(387V) = 387 eV

3 0
3 years ago
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