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nasty-shy [4]
3 years ago
8

What is the relationship between the mass of an object and the amount of force required to drag it across the table?

Physics
1 answer:
hammer [34]3 years ago
6 0

Answer:

Force = mass × acceleration

Explanation:

The amount of force required to drag the object across the table is the product of the mass of the object and acceleration

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anice is watching her granddaughter drive a Barbie Jeep with a 6 V battery and an electric motor with 5 ohm of resistance. How m
Scrat [10]

Answer:

Power required will be 7.2 watt

Explanation:

We have given battery of Barble jeep is 6 volt

So potential difference V = 6 volt

Resistance of electric motor R = 5 ohm '

We have to find the power motor using to drive the jeep

Power is given by P=\frac{V^2}{R}, here V is voltage and R is resistance

So P=\frac{V^2}{R}=\frac{6^2}{5}=7.2watt

5 0
3 years ago
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Which circuit generates the most power
Tom [10]

Answer:

parallel circuit

Explanation:

In a parallel circuit, the potential difference across each of the resistors that make up the circuit is the same. This leads to a higher current flowing through each resistor and subsequently the total current flowing through all the resistors is higher.

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The main difference between speed and velocity involves
mars1129 [50]

Velocity is speed plus the direction of the speed.

6 0
3 years ago
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On a frictionless surface how much force is necessary to accelerate a 0.49 kg object to the left at 4.8 m/s2?
Alenkasestr [34]

Answer:

<h2>2.35 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question

force = 0.49 × 4.8 = 2.352

We have the final answer as

<h3>2.35 N</h3>

Hope this helps you

8 0
2 years ago
How will a current change if the resistance of a circuit remains constant while the voltage across the circuit decreases to half
beks73 [17]

Answer:

1. The current will drop to half of its original value.

Explanation:

The problem can be solved by using Ohm's law:

V=RI

where

V is the voltage across the circuit

R is the resistance of the circuit

I is the current

We can rewrite it as

I=\frac{V}{R}

In this problem, we have:

- the resistance of the circuit remains the same: R' = R

- the voltage is decreased to half of its original value: V'=\frac{V}{2}

So, the new current will be

I'=\frac{V'}{R'}=\frac{V/2}{R}=\frac{1}{2}\frac{V}{R}=\frac{I}{2}

so, the current will drop to half of its original value.

4 0
2 years ago
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