2 years ago

Which of the following is NOT a benefit of cool down activities?

Physics

1 answer:

True [87]2 years ago

3 0

Answer:

Blood is moved away from the brain

Explanation:

Took the test

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Water is used to cool down automobile engines when they get hot. Why is water used as a coolant? A. Water is a good conductor. B

Mrac [35]

Water is usually used to cool down automobile engines when they get hot, yes. Therefore, that means water has a high heat capacity.

That makes the answer letter D you provided above.

D) Water has a high heat capacity.

Another example would be trying to put out a fire with a bucket of water. Usually, you can put out the fire debating on the size!

3 0

3 years ago

Read 2 more answers

A sample of chlorine has two naturally occurring isotopes. The isotope Cl-35 (mass 35.0 amu) makes up 75.8% of the sample, and t

irinina [24]

Answer:

$M_{av}=35.521amu$

Explanation:

As in any sample you will have 75.8% of Cl-35 iosotopes and 24.3% of Cl-37 iosotopes you can get the average atomic mass as:

$M_{av}=(35amu*75.8+37amu*24.3)/100=35.521amu$

4 0

2 years ago

During the fission reaction shown, how did the target nucleus change ?

Zarrin [17]

Answer:

A. The target nucleus split into two nuclei, each with fewer nucleons than the original.

Explanation:

5 0

3 years ago

While strolling downtown on a Saturday afternoon, you stumble across an old car show. As you are walking along an alley toward a

snow_tiger [21]

Answer:

1.44 m/s²

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

$v=u+at\\\Rightarrow v=0+a\times 5\\\Rightarrow v=5a$

This velocity will be the initial velocity of the car when it passes through the first building

$s=ut+\frac{1}{2}at^2\\\Rightarrow 3=5a\times 0.4+\frac{1}{2}\times a\times 0.4^2\\\Rightarrow a=1.44\ m/s^2$

The acceleration of the car is 1.44 m/s²

7 0

3 years ago

5 points

olga2289 [7]

Answer:

d. 5 ohms

Explanation:

For resistors in parallel, the equivalent resistance is found with:

1/Req = ∑(1/R)

1/R = 1/15 + 1/15 + 1/15

1/R = 3/15

R = 15/3

R = 5

8 0

3 years ago