Answer:
A=False
B=False
C=False
D=False
E=False
F=False
Explanation:
A. In an isothermal process, only the reversibly heat transfer is 0, 
B. Consider the phase change of boiling water. Here, the temperature remains constant but the internal energy of the system increases.
C. This is not true even in reversible process, as can be inferred from the equation in part A.
D. This is only true in reversible processes, but not in all isothermal processes.
E. Consider the phase change of freezing water. Here, the surroundings are increasing their entropy, as they are taking in heat from the system.
F. This is not true if 
, like in answer B. One case where this is true is in the reversible isothermal expansion (or compression) of an ideal gas.
Answer:
lastName.compareTo("Dexter")>0
Explanation:
The expression that evaluates to true if the value of variable lastName is greater than the string Dexter is; lastName.compareTo("Dexter")>0.
Answer:
2.83 kg
Explanation:
Given:
Volume, V = 0.8 m³
gage pressure, P = 200 kPa
Absolute pressure = gage pressure + Atmospheric pressure
= 200 + 101 = 301 kPa = 301 × 10³ N/m²
Temperature, T = 23° C = 23 + 273 = 296 K
Now,
From the ideal gas equation
PV = mRT
Where,
m is the mass
R is the ideal gas constant = 287 J/Kg K. (for air)
thus,
301 × 10³ × 0.8 = m × 287 × 296
or
m = 2.83 kg
The complete stress distribution obtained by superposing the stresses produced by an axial force and a bending moment is correctly represented by F/A - (My)/(Iz).
<h3>What is the distribution of pressure at some stage in bending?</h3>
Compressive and tensile forces expand withinside the path of the beam axis beneath neath bending loads. These forces set off stresses at the beam. The most compressive pressure is observed on the uppermost fringe of the beam whilst the most tensile pressure is positioned on the decrease fringe of the beam.
The bending pressure is computed for the rail through the equation Sb = Mc/I, wherein Sb is the bending pressure in kilos in keeping with rectangular inch, M is the most bending second in pound-inches, I is the instant of inertia of the rail in (inches)4, and c is the space in inches from the bottom of rail to its impartial axis.
Read more about beam;
brainly.com/question/25329636
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Answer:
Fuel efficiency for highway = 114.08 miles/gallon
Fuel efficiency for city = 98.79 miles/gallon
Explanation:
1 gallon = 3.7854 litres
1 mile = 1.6093 km
Let's first convert the efficiency to km/gallon:
48.5 km/litre = (48.5 * 3.7854) km/gallon
48.5 km/litre = 183.5919 km/gallon (highway)
42.0 km/litre = (42.0 * 3.7854) km/gallon
42.0 km/litre = 158.9868 km/gallon (city)
Next, we convert these to miles/gallon:
183.5919 km/gallon = (183.5919 / 1.6093) miles/gallon
183.5919 km/gallon = 114.08 miles/gallon (highway)
158.9868 km/gallon = (158.9868 /1.6093) miles/gallon
158.9868 km/gallon = 98.79 miles/gallon (city)
