What are the success factors for mechanical engineering?
2 answers:
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Image of wheel is missing, so i attached it.
Answer:
ω = 14.95 rad/s
Explanation:
We are given;
Mass of wheel; m = 20kg
T = 20 N
k_o = 0.3 m
Since the wheel starts from rest, T1 = 0.
The mass moment of inertia of the wheel about point O is;
I_o = m(k_o)²
I_o = 20 * (0.3)²
I_o = 1.8 kg.m²
So, T2 = ½•I_o•ω²
T2 = ½ × 1.8 × ω²
T2 = 0.9ω²
Looking at the image of the wheel, it's clear that only T does the work.
Thus, distance is;
s_t = θr
Since 4 revolutions,
s_t = 4(2π) × 0.4
s_t = 3.2π
So, Energy expended = Force x Distance
Wt = T x s_t = 20 × 3.2π = 64π J
Using principle of work-energy, we have;
T1 + W = T2
Plugging in the relevant values, we have;
0 + 64π = 0.9ω²
0.9ω² = 64π
ω² = 64π/0.9
ω = √64π/0.9
ω = 14.95 rad/s
Answer:
diameter is 14.83 mm
Explanation:
given data
height = 2 mm
to find out
internal diameter
solution
we consider here material is glass and liquid is water and angle is zero if no capillary rise
we apply here capillary rise formula that is
Capillary rise h = 2T / [ r×ρ×g ] ....................1
put here r is radius and ρ = 1000 kg/m³, T = 72.7 × N/m all value in equation 1
Capillary rise h = 2T / [ r×ρ×g ]
r = 2T / [ h×ρ×g ]
d/2 = 2T / [ h×ρ×g ]
d/2 = 2( 72.7 ×) / [ 2×
×1000×9.8 ]
d = 0.0148336 m
so diameter is 14.83 mm