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fgiga [73]
3 years ago
5

Which of these actions can be taken to minimize number of victims or prevent injury? (check all that apply) A. Hire good lawyers

to defend those responsible for the disater. B. Regular inspections of man-made structures by licensed inspectors. C. Alarm systems and plans for evacuation and shelter of all communities neighboring a site of a potential disaster. D. Include fail-safe mechanisms in the design of life-critical systems
Engineering
1 answer:
Alenkasestr [34]3 years ago
5 0

Answer:

The options that apply are:

B, C and D.

Explanation:

There have been a number of accidents all over the world resulting from Acts of God, professional negligence amongst other things.

These may not be avoided completely but the actions above speak to how they can be mitigated or reduced.

Cheers!

You might be interested in
Compact fluorescent bulbs are much more efficient at producing light than are ordinary incandescent bulbs. They initially cost m
Ilia_Sergeevich [38]

Answer:

ordinary bulb total cost is $39.54

fluorescent bulb total cost is $13.05

amount save = 39.54 - 13.05 = $26.49

resistance = 626.1 ohm

Explanation:

in the 1st part

bulb on time = 3 year = 4380 hours

life of bulb = 750 h

so number of bulb required = \frac{4380}{750}

number of bulb required = 6

cost of 6 bulb is = 6 × 0.75 = $4.5

so

cost of operation is = 100 × 4380 × \frac{0.08}{1000}

cost of operation = $35.04

so total cost will be = $4.5 + $35.04  = $39.54

and

when compare with florescent bulb

time = 3 year = 4380 h

life of bulb = 10000 h

so number of bulb required = \frac{4380}{10000}

number of bulb required = 0.43 = 1

cost of 6 bulb is = 1 × 5 = $5

so

cost of operation is = 23 × 4380 × \frac{0.08}{1000}

cost of operation = $8.05

so total cost will be = $5 + $8.05  = $13.05

in part 2nd

total amount save while compare bulb is

amount save = 39.54 - 13.05 = $26.49

and in part 3rd

resistance of bulb is

resistance = \frac{v^2}{P}

resistance = \frac{120^2}{23}

resistance = 626.1 ohm

6 0
3 years ago
Thin film deposition is a process where: a)-elemental, alloy, or compound thin films are deposited onto a bulk substrate! b)-Pho
marshall27 [118]

Answer:

(A) elemental, alloy, or compound thin films are deposited on to a bulk substrate

Explanation:

In film deposition there is process of depositing of material in form of thin films whose size varies between the nano meters to micrometers onto a surface. The material can be a single element a alloy or a compound.

This technology is very useful in semiconductor industries, in solar panels in CD drives etc

so from above discussion it is clear that option (a) will be the correct answer

8 0
3 years ago
To revise a monthly budget, changes in which categories might need to be addressed? Check all that apply.
GREYUIT [131]

Income

amount budgeted

expenses

5 0
2 years ago
A) For Well A, provide a cross-section sketch that shows (i) ground elevation, (ii) casing height, (iii) depth to
Ad libitum [116K]
Don’t go on that file will give a virus! Sorry just looking out and I don’t know how to comment!
7 0
3 years ago
If a heat engine has an efficiency of 30% and its power output is 600 W, what is the rate of heat input from the combustion phas
jarptica [38.1K]

Answer:

The heat input from the combustion phase is 2000 watts.

Explanation:

The energy efficiency of the heat engine (\eta), no unit, is defined by this formula:

\eta = \frac{\dot W}{\dot Q} (1)

Where:

\dot Q - Heat input, in watts.

\dot W - Power output, in watts.

If we know that \dot W = 600\,W and \eta = 0.3, then the heat input from the combustion phase is:

\eta = \frac{\dot W}{\dot Q}

\dot Q = \frac{\dot W}{\eta}

\dot Q = \frac{600\,W}{0.3}

\dot Q = 2000\,W

The heat input from the combustion phase is 2000 watts.

8 0
2 years ago
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