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pshichka [43]
3 years ago
11

Ground squirrels inhabit African savannas. Which adaptation helps the ground squirrels live in this biome?

Chemistry
2 answers:
Alex73 [517]3 years ago
6 0

Answer: The only possibly answer that makes the most logical sense is a

Explanation: B. wouldn't make it any better only worse making the population die out it would help more in a cold C. doesn't make sense either their ground squirrels but they can still climb and finally D. there in Africa everything is basically beige and they would stick out more making them easy prey.

A makes it easier to blend in with their surroundings and giving them a higher survival chance

meriva3 years ago
3 0

Answer:little did he know that the answer to this problem was A the answer is A

Explanation:

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Answer:

A. 0 N

Explanation:

One force is subtracted from the other to calculate the net force. If the opposing forces are equal, or balanced, the net force is zero.

Hope this helps!

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3 years ago
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2 years ago
You react 2.43 grams of magnesium with oxygen from the air according to the following reaction. The final mass of the product, m
Leona [35]

Answer:

The mass of oxygen that reacted is approximately 1.6 grams of oxygen

Explanation:

The given information are;

The mass of magnesium in the reaction = 2.43 grams

The final mass of the magnesium oxide = 4.12 grams

The chemical equation for the reaction is given as follows;

2Mg + O₂  →  2MgO

From which we see that two moles of magnesium, Mg, reacts with one mole of oxygen gas molecule, O₂, to produce two moles of magnesium oxide, MgO

The number of moles of magnesium present, n_{Mg}, is given as follows;

n_{Mg} = \dfrac{Mass \ of \, magnesium}{Molar \ mass \ of \, magnesium} = \dfrac{2.43}{24.305} \approx 0.1 \ moles

By the given chemical equation, 2 moles of magnesium reacts with one mole of O₂, therefore;

1 mole of magnesium will react with 1/2  moles of oxygen which is 0.5 moles of oxygen also;

0.1 mole of magnesium will react with 0.05 moles of oxygen

The mass of one mole of oxygen = The molar mass of oxygen = 32 g/mol

The mass of oxygen in the reaction = The number of moles of oxygen × The molar mass of oxygen

The mass of oxygen in the reaction = 0.05 × 32 = 1.6 grams

Also from the molar mass  of MgO which is 40.3044 g/mol, we have;

The mass fraction of oxygen = 16/40.3044 = 0.39698 ≈ 0.4

The mass of oxygen = 0.39698 × 4.12 = 1.636 g

Therefore, the mass of oxygen in the reaction is approximately 1.6 grams.

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3 years ago
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Leni [432]

Answer:

false

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3 years ago
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