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2 years ago

Help me with this pls

Mathematics

2 answers:

zzz [600]2 years ago

6 0

Answer:

The answer should be D) 60 = (x + 45)

Step-by-step explanation:

bazaltina [42]2 years ago

3 0

Answer:

D. 60=(x+45)

Step-by-step explanation:

They are the same degree so they should equal eachother

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Please answer ASAP will mark brainilest

Otrada [13]

Answer:

Step-by-step explanation:

Change of Y is 0 and change of x is any number.

0/any number = 0

6 0

3 years ago

Find the area of the lateral faces of the right triangular prism with altitude of 5 cm and base edges of length 3 cm, 4 cm, and

Marysya12 [62]

Check the picture below.

the base of it is one of the triangles, and thus, the sides are just the 3 rectangles.

notice all you have is a 3x5 rectangle, a 5x5 one and a 4x5 rectangle.

get their area, sum them up, and that's the lateral, sides, area of the triangular prism.

(3 · 5) + (5 · 5) + (4 · 5)

6 0

2 years ago

Assume that population mean is to be estimated from the sample described. Use the sample results to approximate the margin of er

Vikentia [17]

Answer:

$ME=1.998 \frac{4}{\sqrt{64}}=0.999 \approx 1$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X =69$ represent the sample mean for the sample

$\mu$ population mean

s=4.0 represent the sample standard deviation

n=64 represent the sample size

Assuming the X follows a normal distribution

$X \sim N(\mu, \sigma)$

The sample mean $\bar X$ have the following distribution:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

The margin of error for the sample mean is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

Since we have the sample standard deviation we can estimate the margin of error like this:

$ME=t_{\alpha/2}\frac{s}{\sqrt{n}}$

The next step would be find the value of $\z_{\alpha/2}$ , $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$

We can find the degrees of freedom like this:

$df=n-1=64-1=63$

And we can find the critical value with the following code in excel for example: "=T.INV(0.025,63)" and we got:

$t_{\alpha/2}=\pm 1.998$

And the margin of error would be :

$ME=1.998 \frac{4}{\sqrt{64}}=0.999 \approx 1$

3 0

3 years ago

What is the area of the rhombus shown below?

zzz [600]

Answer:

Step-by-step explanation:

i took test

5 0

3 years ago

Blake and James are planning to go on a trip. Blake already has some money saved. She earns $96 more by working overtime. James

rosijanka [135]

Blake saved $\bold{\$ 433.80}$

Option - A

<u>SOLUTION: </u>

Given, Blake and James are planning to go on a trip.

Blake already has some money saved.

Let the amount saved by Blake be $\$ n$ .

She earns $\$96$ more by working overtime.

Then, total amount by Blake $=\$(n+96)$

James has $\$ 53$ more than 4 times the amount of money that Blake has saved.

Then, total amount by James will be $\$ 53+4 \times \$ n=\$(4 n+53)$

If they have $\$2,318$ in all, we have to find how much money had Blake originally saved

Now, total amount = $\$2318$

$\begin{array}{l}{\rightarrow \text { Amount by Blake }+\text { amount by James }=2318} \\\\ {\rightarrow \mathrm{n}+96+4 \mathrm{n}+53=2318 \rightarrow 5 \mathrm{n}+149=2318 \rightarrow 5 \mathrm{n}=2318-149 \rightarrow 5 \mathrm{n}=2169 \rightarrow \mathrm{n}=433.8}\end{array}$

7 0

3 years ago