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lidiya [134]
3 years ago
6

What is the mass of a box that accelerates to 10 m/s/s with a 70 Newton push?

Physics
1 answer:
Allisa [31]3 years ago
8 0

Answer:

Mass of box = 7 kg

Explanation:

Force = 70 N

Acceleration = 10 m/s²

Force is product of mass and acceleration.

\longrightarrow Force = Mass × Acceleration

\longrightarrow 70 = Mass × 10

\longrightarrow Mass = \sf \dfrac{70}{10}

\longrightarrow Mass = 7 kg

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The answer is not B.
mezya [45]

Answer:

D

Explanation:

15m/ s

i hope this helps

4 0
2 years ago
After Moseley's discovery in 1913, the periodic law stated that physical and chemical properties tend to repeat periodically whe
stich3 [128]

Answer:

Option B

Explanation:

The correct answer is Option B.

Before Moseley's discovery in 1913, In Mendeleev's periodic table the elements rearranged with increasing atomic mass.

Mendeleev was not able to locate hydrogen atom and late isotopes found violate Mendeleev table. The biggest drawback was that the atomic mass was not regular when moving one element to another.

But Moseley's arranged element in the periodic table with increasing atomic number.  

3 0
3 years ago
How far away is mars from the sun. why is is red?
Degger [83]
Mars is 139.58 million miles away from the sun. mars is red because its soil has iron oxide (rust particles) in it.
7 0
3 years ago
Dr. Kirwan is preparing a slide show that he will present to the executive board at tonight's committee meeting. He places a 3.5
lisov135 [29]

Answer:

A) d_o = 20.7 cm

B) h_i = 1.014 m

Explanation:

A) To solve this, we will use the lens equation formula;

1/f = 1/d_o + 1/d_i

Where;

f is focal Length = 20 cm = 0.2

d_o is object distance

d_i is image distance = 6m

1/0.2 = 1/d_o + 1/6

1/d_o = 1/0.2 - 1/6

1/d_o = 4.8333

d_o = 1/4.8333

d_o = 0.207 m

d_o = 20.7 cm

B) to solve this, we will use the magnification equation;

M = h_i/h_o = d_i/d_o

Where;

h_o = 3.5 cm = 0.035 m

d_i = 6 m

d_o = 20.7 cm = 0.207 m

Thus;

h_i = (6/0.207) × 0.035

h_i = 1.014 m

8 0
3 years ago
The angle θ is slowly increased. Write an expression for the angle at which the block begins to move in terms of μs.
Reika [66]

Answer:

tan \theta = \mu_s

Explanation:

An object is at rest along a slope if the net force acting on it is zero. The equation of the forces along the direction parallel to the slope is:

mg sin \theta - \mu_s R =0 (1)

where

mg sin \theta is the component of the weight parallel to the slope, with m being the mass of the object, g the acceleration of gravity, \theta the angle of the slope

\mu_s R is the frictional force, with \mu_s being the coefficient of friction and R the normal reaction of the incline

The equation of the forces along the direction perpendicular to the slope is

R-mg cos \theta = 0

where

R is the normal reaction

mg cos \theta is the component of the weight perpendicular to the slope

Solving for R,

R=mg cos \theta

And substituting into (1)

mg sin \theta - \mu_s mg cos \theta = 0

Re-arranging the equation,

sin \theta = \mu_s cos \theta\\\rightarrow tan \theta = \mu_s

This the condition at which the equilibrium holds: when the tangent of the angle becomes larger than the value of \mu_s, the force of friction is no longer able to balance the component of the weight parallel to the slope, and so the object starts sliding down.

4 0
4 years ago
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