Question

The vertices of a polygon are P(0,4), Q(5,4), R(5,−3) and S(0,−3). What is

Answer 1

Answer:

 Perimeter of the polygon p = 24

Step-by-step explanation:

Step(i):-

Given the vertices of a polygon are

P(0,4) ,Q( 5,4) ,R( 5,-3) and S(0,-3)

The distance of PQ

 $a = PQ = \sqrt{(4-4)^{2} +(5-0)^{2} } = \sqrt{25} =5$

The distance of QR

$b = Q R= \sqrt{(-3-4)^{2} +(5-5)^{2} } = \sqrt{49} =7$

The distance of RS

$c = RS = \sqrt{(0-5)^{2} +(-3+3)^{2} } = \sqrt{25} =5$

The distance of PS

$d = PS = \sqrt{(0-0)^{2} +(-3-4)^{2} } = \sqrt{49} =7$

Step(ii):-

Perimeter of the polygon

       = sum of all sides of polygon

p = a+ b+ c+ d

p = 5+7+5+7

p = 24

Final answer:-

 Perimeter of the polygon p = 24