Find the volume and surface area of cube having lenght =5cm

Mathematics

2 answers:

hoa [83]3 years ago

5 0

Step-by-step explanation:

Volumeof cube = s³

= 5³

=125cm³

Surface area of cube = 6•s²

= 6 x 5²

= 6 x 25

= 150cm²

notka56 [123]3 years ago

3 0

v=l³

v=5³

v=125cm³#

Step-by-step explanation:

hope you like it

You might be interested in

An international company has 13,600 employees in one country. If this represents 19.3% of the company's employees, how many empl

user100 [1]

Hi there! To solve this question, we can write and solve a proportion. Let’s set it up like this: 13,600/x = 19.3/100. We do this, because we’re looking for the total amount of people, which would be the whole. We already have the part. Cross multiply the values in order to get 1,360,000 = 19.3x. Now, divide each side by 19.3 to isolate the variable. When you do, you get x is approx. 70,466.3212 or 70,466 when rounded to the nearest whole number. Plus, you can’t have a fraction of a person, anyway. The company has a total of 70,466 employees.

4 0

3 years ago

What do you think ? compared to bottoms up method: better, Worse, the same or something Else?

Leya [2.2K]

Idk what u mean.......

3 0

3 years ago

How to find variables of these #2 & #3

Lubov Fominskaja [6]

So... hmmm if you check the first picture below, for 2)

we could use the proportions of those small, medium and large similar triangles like $\bf \cfrac{small}{large}\qquad \cfrac{x}{12}=\cfrac{6}{x}\impliedby \textit{solve for "x"}
\\\\\\
\cfrac{small}{large}\qquad \cfrac{z}{18}=\cfrac{6}{z}\impliedby \textit{solve for "z"}
\\\\\\
\cfrac{large}{medium}\qquad \cfrac{y}{12}=\cfrac{18}{y}\impliedby \textit{solve for "y"}$

now.. for 3) will be the second picture below

$\bf \cfrac{large}{medium}\qquad \cfrac{x+10}{2\sqrt{30}}=\cfrac{2\sqrt{30}}{10}\impliedby \textit{solve for "x"}
\\\\\\
\textit{now, because you already know what "x" is, we can use it below}
\\\\\\
\cfrac{large}{small}\qquad \cfrac{z}{x}=\cfrac{x+10}{z}\impliedby \textit{solve for "z"}
\\\\\\
\textit{and let us use "x" again below}
\\\\\\
\cfrac{small}{medium}\qquad \cfrac{y}{10}=\cfrac{x}{y}\impliedby \textit{solve for "y"}$