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2 years ago

Find the volume and surface area of cube having lenght =5cm

Mathematics

2 answers:

hoa [83]2 years ago

5 0

Step-by-step explanation:

Volumeof cube = s³

= 5³

=125cm³

Surface area of cube = 6•s²

= 6 x 5²

= 6 x 25

= 150cm²

notka56 [123]2 years ago

3 0

v=l³

v=5³

v=125cm³#

Step-by-step explanation:

hope you like it

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Find the slope of line that contains the points (-4,-13) and (8,5).

gtnhenbr [62]

We can use y2-y1/x2-x1 to find the slope. Therefore, we have:
-5-(-13)/8-(-4). That gives us -5+13/8+4, or 8/12 = 2/3.
Hope this helps!

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3 years ago

Read 2 more answers

The odometer in a car measures the number of miles driven by the car since it was made. During a trip, the odometer reading in A

telo118 [61]

Answer:

Step-by-step explanation:

Part A

The units on 9500 must be miles. So if x is time, then 55 must be the rate at which she travels ie 55 miles per hour. So the answer must be A.

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3 years ago

Please help me by answering this?

Dmitrij [34]

Answer:

180

Step-by-step explanation:

$\frac{6}{2} x^{2} | \frac{8}{2}$

192-12=180

8 0

2 years ago

Find the volume of the largest rectangular box in the first octant with three faces in the coordinate planes and one vertex in t

Tresset [83]

Answer: The volume of largest rectangular box is 4.5 units.

Step-by-step explanation:

Since we have given that

Volume = $xyz$

with subject to $x+2y+3z=9$

So, let $z=\dfrac{9-x-2y}{3}$

So, Volume becomes,

$V=xyz\\\\V=xy(\dfrac{9-x-2y}{3})\\\\V=\dfrac{9xy-x^2y-2xy^2}{3}$

Partially derivative wrt x and y we get that

$9-2x-2y=0\implies 2x+2y=9\\\\and\\\\9-x-4y=0\implies x+4y=9$

By solving these two equations, we get that

$x=3,y=\dfrac{3}{2}$

So, $z=\dfrac{9-x-2y}{3}=\dfrac{9-3-3}{3}=\dfrac{3}{3}=1$

So, Volume of largest rectangular box would be

$xyz=3\times \dfrac{3}{2}\times 1=\dfrac{9}{2}=4.5$

Hence, the volume of largest rectangular box is 4.5 units.

4 0

3 years ago

Moira said, "If a right triangle has one side with a length of 3 units and one side with a length

Dima020 [189]

If the two sides with length 3 and 4 are the two legs, then the missing side, i.e. the hypotenuse, is indeed 5.

But it could also be the case that 4 is the hypotenuse and 3 is one of the legs. In this case, the missing side is the other leg, so we calculate it using

$\sqrt{4^2-3^2}=\sqrt{16-9}=\sqrt{7}$

So, a right triangle with legs $\sqrt{7}$ and 3 has an hypotenuse of 4.

8 0

3 years ago