24.
This is because if we double the base and the height in the area equation it will raise any number by a factor of 4.
12×4=48 , 68×12 is a much greater number.
Answer:
The line slopes upwards from left to right wit a positive gradient and cuts the y-axis at y=2 and the x-axis at x=-3/2
Step-by-step explanation:
We first rearrange the equation to the order y=mx+c where m is the gradient and c the y intercept.
3y=4x+6
y=(4/3)x+2
The gradient is therefore 4/3 and the y intercept is 2.
At the c intercept, y=0
0=(4/3)x +2
(4/3)x=-2
x=-2×3/4
=3/2
The line slopes upwards from left to right with a positive gradient and cuts the y-axis at y=2 and the x-axis at x=-3/2
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<h3>Andre Bought:</h3><h3>• 1 Baseball Glove For $34 Each</h3><h3>• 2 Packs of Socks For $6 - 7.75% Each</h3>
<h3 /><h3>$34 + $8</h3><h3>= $42</h3><h3><u>Andre Paid A Total of $42</u></h3>
<h3>7.75% × $6 ÷ 100</h3><h3>= 0.465 × 2</h3><h3>= 0.93%</h3><h3><u>Andre Saved 0.93% In Total At The Sale</u></h3>
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Might have to experiment a bit to choose the right answer.
In A, the first term is 456 and the common difference is 10. Each time we have a new term, the next one is the same except that 10 is added.
Suppose n were 1000. Then we'd have 456 + (1000)(10) = 10456
In B, the first term is 5 and the common ratio is 3. From 5 we get 15 by mult. 5 by 3. Similarly, from 135 we get 405 by mult. 135 by 3. This is a geom. series with first term 5 and common ratio 3. a_n = a_0*(3)^(n-1).
So if n were to reach 1000, the 1000th term would be 5*3^999, which is a very large number, certainly more than the 10456 you'd reach in A, above.
Can you now examine C and D in the same manner, and then choose the greatest final value? Safe to continue using n = 1000.
