%= total atomic mass of element/formula mass of the compoundX100
atomic mass(Ar) of sulfur- 32
Ar of Cu- 64
Ar of O-16
64+32+(16x4)= 160
32/160=0.2
0.2x100=20
20%
Answer:
678 mL.
Explanation:
The balanced reaction between calcium chloride and silver nitrate is shown in figure.
As shown in the equation , each mole of aqueous calcium chloride will rect with two moles of silver nitrate.
The moles of calcium chloride taken = molarity X volume (L)
= 0.37X0.33 = 0.122 mol
the moles of silver nitrate required = 2 X 0.122 = 0.244 mol
the volume of silver chloride required =
M = 0.36 M
mol = 0.244
Putting values
volume = 0.678 L = 678 mL.
A unit of mass used to express atomic and molecular weights, equal to one-twelfth of the mass of an atom of carbon-12. It is equal to approximately 1.66 x 10-27<span> kg.</span>
The ionic charge of oxygen is -2.
Hope this helps! ;)
Control or controlled group is the part of the experiment where conditions are kept the same.