Answer:B) It was not understood by scientific world.
Explanation:
Answer:
D. Axial stress divided by axial strain
Explanation:
Lets take rod is pulled by force P
Stress σ = P/A
We know that
σ = ε E
E= Lets take rod is pulled by force P
Stress σ = P/A
We know that
σ = ε E
σ=Axial stress
ε =Axial Strain = ΔL/L
E= σ/ε
E= Axial stress/Axial Strain
So the modulus of elasticity is the ratio of axial stress to axial strain.
σ=Axial stress
ε =Axial Strain = ΔL/L
E= σ/ε
E= Axial stress/Axial Strain
So the modulus of elasticity is the ratio of axial stress to axial strain.
The option D is correct.
Answer:
0 m/s
Explanation:
Average velocity is displacement over time.
v_avg = Δx / Δt
Displacement is the distance between the start and the finish.
The circumference of the track is:
C = 2πr
C = 2π (7 m)
C ≈ 44 m
The distance covered by the object is:
d = vt
d = (11 m/s) (8 s)
d = 88 m
So the object travels 2 circumferences, meaning it ends back where it started. Therefore, the displacement is 0 m, and the average velocity is 0 m/s.
We can first calculate the net force using the given information.
By Newton's second law, F(net) = ma:
F(net) = 25 * 4.3 = 107.5
We can now calculate the frictional force, f, which is working against the applied force, F(app) (this is why the net force is a bit lower):
f = F(net) - F(app) = 150 - 107.5 = 42.5 N
Now we can calculate the coefficient of friction, u, using the normal force, F(N):
f = uF(n) --> u = f/F(N)
u = 42.5/[25(9.8)]
u = 0.17