Answer:
Given force=10lb
L1=4in converting to feet
But 0.08333ft= 1 inch
Then 4 inch is 0.3332
6inch is 0.49998
But hookes law states
F=Kx where F is force,K is the force constant ,X
K=F/X=10/0.3333=30N/m
Integrating this
Integral of 30x with limit 0.333 to 0.5
F=30x^2/2=15x^2substing the limit
F=(15(0.5^2-0.33^2)=2.08ft-lb
Explanation:
D)
<span>No. the products include He-4, one neutron, and energy.</span>
Answer:
charges of the beads is 1.173 ×
C
Explanation:
given data
mass = 3.8589 g = 0.003859 kg
spring length = 5 cm = 0.05 m
extend spring x = 1.5747 cm = 0.15747 m
spring's extension = 0.0116 m
to find out
charges of the beads
solution
we know that force is
force = mass × g
force = 0.003859 × 9.8
force = 0.03782 N
so we know force for mass
force = -kx
so k = force / x
put here force and x value
k = -0.03782 / 0.1575
k = -0.24 N/m
and
force for spring's extension
force = -kx
force = -0.24 ( 0.0116) = 0.002784 N
so here
total length L = 0.05 + 0.0116 = 0.0616
so charges of the beads = force × L² / ke
charges of the beads = 0.002784 × (0.0616)² / (9 ×
)
so charges of the beads = 1.173 ×
C
Answer:2.6 h
Explanation:
Given
Total Trip distance=450 miles
Meeting starts after 10.8 hours
safe Fastest speed is 55 mi/h
so if he drives all the to the meeting with max speed then it takes 
and total allowable time is 10.8
Therefore longest time he can spend over dinner is 