The impulse experienced is -18,000 kg m/s
Explanation:
The impulse exerted on an object is equal to the change in momentum of the object. Mathematically:
where
m is the mass of the object
v is the final velocity of the object
u is the initial velocity
is the change in momentum
I is the impulse
In the collision in this problem,
m = 1300 kg is the mass of the car
u = 11 m/s is the initial velocity
v = -2.5 m/s is the final velocity (negative, since it is in the opposite direction)
Substituting, we find
So the closest choice is
-18,000 kg m/s
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Albert Einstein, in his theory of special relativity, determined that the laws of physics are the same for all non-accelerating observers, and he showed that the speed of light within a vacuum is the same no matter the speed at which an observer travels
Answer:
The equation of equilibrium at the top of the vertical circle is:
\Sigma F = - N - m\cdot g = - m \cdot \frac{v^{2}}{R}
The speed experimented by the car is:
\frac{N}{m}+g=\frac{v^{2}}{R}
v = \sqrt{R\cdot (\frac{N}{m}+g) }
v = \sqrt{(5\,m)\cdot (\frac{6\,N}{0.8\,kg} +9.807\,\frac{kg}{m^{2}} )}
v\approx 9.302\,\frac{m}{s}
The equation of equilibrium at the bottom of the vertical circle is:
\Sigma F = N - m\cdot g = m \cdot \frac{v^{2}}{R}
The normal force on the car when it is at the bottom of the track is:
N=m\cdot (\frac{v^{2}}{R}+g )
N = (0.8\,kg)\cdot \left(\frac{(9.302\,\frac{m}{s} )^{2}}{5\,m}+ 9.807\,\frac{m}{s^{2}} \right)
N=21.690\,N
Answer:
It loses electrons.
Explanation:
Electrons have a negative charge meaning ,the less electrons there are in an object the stronger the positive charge is.
Answer:
Explanation:
When heat energy is supplied to an object, the temperature of the object increases according to the equation:
where
Q is the heat supplied
C is the heat capacity of the object
is the change in temperature
In this problem we have:
is the energy supplied
is the change in temperature of the object
Therefore, the heat capacity of the object is:
