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Leviafan [203]
3 years ago
8

Once a sound recording is made, how is the sound reproduced? by converting passive sound waves into active sound waves by conver

ting sound waves into electronic signals by converting the electronic signals back into sound waves by speeding up the stored sound waves
Physics
2 answers:
In-s [12.5K]3 years ago
8 0

it converts into sizes

lubasha [3.4K]3 years ago
7 0

Answer:

by converting the electronic signals back into sound waves

Explanation:

When sound is recorded then we convert the sound energy into electrical energy and store it on the magnetic tapes

Now when we have to convert this energy again into sound then we use the reverse phenomenon.

So in this reverse phenomenon we have to convert the electrical energy stored on the magnetic tapes into the sound energy so overall we can say that correct answer will be

by converting the electronic signals back into sound waves

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force of 10 lb is required to hold a spring stretched 4 in. beyond its natural length. How much work W is done in stretching it
Yanka [14]

Answer:

Given force=10lb

L1=4in converting to feet

But 0.08333ft= 1 inch

Then 4 inch is 0.3332

6inch is 0.49998

But hookes law states

F=Kx where F is force,K is the force constant ,X

K=F/X=10/0.3333=30N/m

Integrating this

Integral of 30x with limit 0.333 to 0.5

F=30x^2/2=15x^2substing the limit

F=(15(0.5^2-0.33^2)=2.08ft-lb

Explanation:

3 0
3 years ago
H-2 + H-3 → He-4 +
Svetach [21]
D)
<span>No. the products include He-4, one neutron, and energy.</span>
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3 years ago
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A 5 cm spring is suspended with a mass of 3.8589 g attached to it which extends the spring by 1.5747 cm. The same spring is plac
lana66690 [7]

Answer:

charges of the beads is 1.173 ×10^{-15} C

Explanation:

given data

mass = 3.8589 g = 0.003859 kg

spring length = 5 cm = 0.05 m

extend spring x = 1.5747 cm = 0.15747 m

spring's extension = 0.0116 m

to find out

charges of the beads

solution

we know that force is

force = mass × g

force = 0.003859 × 9.8

force = 0.03782 N

so we know  force for mass

force  = -kx

so k = force / x

put here force and x value

k = -0.03782 / 0.1575

k = -0.24 N/m

and

force for spring's extension

force = -kx

force = -0.24 ( 0.0116) = 0.002784 N

so here

total length L = 0.05 + 0.0116 = 0.0616

so charges of the beads = force × L² / ke

charges of the beads = 0.002784 × (0.0616)² / (9 ×10^{9} )

so charges of the beads = 1.173 ×10^{-15} C

3 0
3 years ago
Arunner has a speed of 23 m/s. They see the finish line and speed up to 27 m/s. This happens in 5 seconds. If the runner has a m
sp2606 [1]
The answer is 100

Have a great day
6 0
3 years ago
You leave on a 450 miles trip in order to attend a meeting that will start 10.8 hours after you begin your trip. Along the way y
Lorico [155]

Answer:2.6 h

Explanation:

Given

Total Trip distance=450 miles

Meeting starts after 10.8 hours

safe Fastest speed is  55 mi/h

so if he drives all the to the meeting with max speed then it takes =\frac{450}{55}=8.181 h

and total allowable time is 10.8

Therefore longest time he can spend over dinner is 10.8-8.181 \approx 2.6 hours

5 0
3 years ago
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