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telo118 [61]
2 years ago
10

A different group is worried that the motion detector will not

Physics
1 answer:
nekit [7.7K]2 years ago
6 0

The energy is not  conserved because:

1. Energy may still be leaving the system through friction.

2. There could be measurement error that account for the missing energy

Given that a different group roll a round  object down a ramp instead of dropping it. They measure the initial  height to calculate gravitational potential energy, use the motion  detector to track the final velocity, and calculate the kinetic energy of  the object at the end.

Despite all their careful measurements, it appears that energy is not

conserved because

1. Energy may still be leaving the system through friction. In which the energy lost will be converted to thermal energy

2. There could be measurement error that account for the missing energy. The may occur due to systematic error or parallax error

The object is not moving as fast at the bottom as the initial gravitational potential would have led them to predict. This is not as a result of rotational energy. There is nothing like rotational energy.

Learn more here: brainly.com/question/23503524

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A proton is confined to a space 1 fm wide (about the size of an atomic nucleus). What's the minimum uncertainty in its velocity?
Daniel [21]

Answer:

Minimum uncertainty in velocity of a proton,\Delta v\ge 3.15\times 10^7\ m/s      

Explanation:

It is given that,

A proton is confined to a space 1 fm wide, \Delta x=10^{-15}\ m

We need to find the minimum uncertainty in its velocity. We know that the Heisenberg Uncertainty principle gives the uncertainty between position and the momentum such that,

\Delta p.\Delta x\ge \dfrac{h}{4\pi}

Since, p = mv

\Delta (mv).\Delta x\ge \dfrac{h}{4\pi}

m \Delta v.\Delta x\ge \dfrac{h}{4\pi}

\Delta v\ge \dfrac{h}{4\pi m\Delta x}

\Delta v\ge \dfrac{6.63\times 10^{-34}}{4\pi \times 1.67\times 10^{-27}\times 10^{-15}}

\Delta v\ge 3.15\times 10^7\ m/s

So, the minimum uncertainty in its velocity is greater than 3.15\times 10^7\ m/s. Hence, this is the required solution.

3 0
3 years ago
A typical laboratory centrifuge rotates at 3700 rpm . Test tubes have to be placed into a centrifuge very carefully because of t
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Answer:

Explanation:

acceleration of test tube

= ω² R

= (2πn)² R

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n = no of rotation per second

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R = .10 m

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= 4π²n²R

= 4 x 3.14² x 61.67² x .10

= 14999 N Approx

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