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3 years ago

A different group is worried that the motion detector will not

Physics

1 answer:

nekit [7.7K]3 years ago

6 0

The energy is not conserved because:

1. Energy may still be leaving the system through friction.

2. There could be measurement error that account for the missing energy

Given that a different group roll a round object down a ramp instead of dropping it. They measure the initial height to calculate gravitational potential energy, use the motion detector to track the final velocity, and calculate the kinetic energy of the object at the end.

Despite all their careful measurements, it appears that energy is not

conserved because

1. Energy may still be leaving the system through friction. In which the energy lost will be converted to thermal energy

2. There could be measurement error that account for the missing energy. The may occur due to systematic error or parallax error

The object is not moving as fast at the bottom as the initial gravitational potential would have led them to predict. This is not as a result of rotational energy. There is nothing like rotational energy.

Learn more here: brainly.com/question/23503524

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Describe how a neutral material becomes attracted to a negatively charged object brought near it.

Naddik [55]

Answer:

Electric force

Explanation:

It’s like static stuff

3 0

3 years ago

Early black-and-white television sets used an electron beam to draw a picture on the screen. The electrons in the beam were acce

lutik1710 [3]

Answer:

speed of electrons = 3.25 × $10^{7}$ m/s

acceleration in term g is 3.9 × $10^{17}$ g.

radius of circular orbit is 2.76 × $10^{-4}$ m

Explanation:

given data

voltage = 3 kV

magnetic field = 0.66 T

solution

law of conservation of energy

PE = KE

qV = 0.5 × m × v²

v = $\sqrt{\frac{2qV}{m}}$

v = $\sqrt{\frac{2\times 1.6 \times 10^{-19}\times 3}{9.1\times 10^{-31}}$

v = 3.25 × $10^{7}$ m/s

and

magnetic force on particle movie in magnetic field

F = Bqv

ma = Bqv

a = $\frac{Bqv}{m}$

a = $\frac{0.67\times 1.6\times 10^{-19}\times 3.25\times 10^7}{9.1\times 10^{-31}}$

a = 3.82 × $10^{18}$ m/s²

and acceleration in term g

a = $\frac{3.82\times 10^{18}}{9.81}$

a = 3.9 × $10^{17}$ g

acceleration in term g is 3.9 × $10^{17}$ g.

and

electron moving in circular orbit has centripetal force

F = $\frac{mv^2}{r}$

Bqv = $\frac{mv^2}{r}$

r = $\frac{mv}{Bq}$

r = $\frac{9.1\times 10^{-31}\times 3.25\times 10^7}{0.67\times 1.6\times 10^{-19}}$

r = 2.76 × $10^{-4}$ m

radius of circular orbit is 2.76 × $10^{-4}$ m

8 0

4 years ago

Arbeitsauftrag 2

kramer

Explanation:

<em>The height of the pendulum is measured from the lowest point it reaches (point 3). </em>

At 1, the kinetic energy of the pendulum is zero (because it is not moving), and it has maximum potential energy.

At 2, the pendulum has both kinetic and potential energy, and how much of each it has depends on its height—smaller the height greater the kinetic energy and lower the potential energy.

At 3, the height is zero; therefore, the pendulum has no potential energy, and has maximum kinetic energy.

At 4, the pendulum again gains potential energy as it climbs back up, Again how much of each forms of energy it has depends on its height.

At 5, the maximum height is reached again; therefore, the pendulum has maximum potential energy and no kinetic energy.

Hope this helps :)

8 0

3 years ago

A person pushes a 125 kg object initially at rest on a frictionless surface. The object ends up with a final velocity of 1.40 m/

mr Goodwill [35]

Answer:

a person pushes a 125 kg

Explanation:

8 0

3 years ago

It was a dark and stormy night, when suddenly you saw a flash of lightning. Three-and-a-half seconds later you heard the thunder

Gekata [30.6K]

We're going to multiply the time it took for you to hear thunder (3.5 seconds) by the speed of sound in air (340 m/s)

3.5 x 340 = 1190

The lightning bolt was 1,190 meters away.

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3 years ago