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ryzh [129]
3 years ago
10

HELP ASAPPP PLEASEEEE THER EIS 2 PAGES

Mathematics
1 answer:
lesya [120]3 years ago
8 0

Answer:

ASA. Can be proven congruent

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Peter has money in two savings accounts. One rate is 6% and the other is 14%. If he has $900 more in the 14% account and the tot
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Answer:

  • $1375 at 14%
  • $475 at 6%

Step-by-step explanation:

Let x represent the amount Peter invested at 14%. Then (x-900) is the amount he invested at 6%. His total interest earned is ...

  0.14x + 0.06(x -900) = 221

  0.20x = 275 . . . . . . . . . . . . . . . . add 54, simplify

  x = 1375 . . . . . . . . . . . . . . . . . . . .divide by 0.2; amount invested at 14%

  (x-900) = 475 . . . . . . . . . . . . . . . amount invested at 6%

Peter invested $475 in the 6% account and $1375 in the 14% account.

7 0
3 years ago
WILL GIVE BRAINLIEST PLEASE HELP
Debora [2.8K]

Answer:

the 3 one is the correct answer

Step-by-step explanation:

3 0
3 years ago
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8.52 The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches
sweet [91]

Answer:

Heights of 29.5 and below could be a problem.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches.

This means that \mu = 32, \sigma = 1.5

There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.

Heights at the 5th percentile and below. The 5th percentile is X when Z has a p-value of 0.05, so X when Z = -1.645. Thus

Z = \frac{X - \mu}{\sigma}

-1.645 = \frac{X - 32}{1.5}

X - 32 = -1.645*1.5

X = 29.5

Heights of 29.5 and below could be a problem.

4 0
2 years ago
A group of scientists have been sent on an expedition to test the soil in the Allegheny Mountains. They need to collect samples
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It’s B. 52 units ...
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35 POINT QUESTION!! WILL GIVE BRAINLIEST!!<br><br> Is x + 2 a factor of P(x) = 2x^3 + 5x^2 + 5x + 6?
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Answer:

Yes

Step-by-step explanation:

2

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