Answer:
Step-by-step explanation:
Let x represent the amount Peter invested at 14%. Then (x-900) is the amount he invested at 6%. His total interest earned is ...
0.14x + 0.06(x -900) = 221
0.20x = 275 . . . . . . . . . . . . . . . . add 54, simplify
x = 1375 . . . . . . . . . . . . . . . . . . . .divide by 0.2; amount invested at 14%
(x-900) = 475 . . . . . . . . . . . . . . . amount invested at 6%
Peter invested $475 in the 6% account and $1375 in the 14% account.
Answer:
the 3 one is the correct answer
Step-by-step explanation:
Answer:
Heights of 29.5 and below could be a problem.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches.
This means that 
There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.
Heights at the 5th percentile and below. The 5th percentile is X when Z has a p-value of 0.05, so X when Z = -1.645. Thus


Heights of 29.5 and below could be a problem.
Answer:
Yes
Step-by-step explanation:
2