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4 years ago

Name this structure

Chemistry

2 answers:

Tpy6a [65]4 years ago

6 0

Answer:

where is it?

but i think imma go with nothing

Explanation:

hram777 [196]4 years ago

3 0

Answer:

where is the structure the picture

Explanation:

???

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CuCl2 Determine the name of this compound according to IUPAC nomenclauture. A) copper chloride B) copper (I) chloride C) copper

faltersainse [42]

The answer is copper (II) chloride

5 0

4 years ago

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What volume of H2O is formed at stp when 6.0g of Al is treated with excess NaOH?

Ne4ueva [31]

Answer : The volume of $H_2O$ is 14.784 L.

Solution : Given,

Mass of Aluminium = 6 g

Molar mass of Aluminium = 27 g/mole

First we have to calculate the moles of aluminium.

Moles of Al = $\frac{\text{ Given mass of Al}}{\text{ Molar mass of Al}}=\frac{6g}{27g/mole}=0.22moles$

The given balanced reaction is,

$2NaOH+2Al+6H_2O\rightarrow 2NaAl(OH)_4+3H_2$

From the reaction, we conclude that

2 moles of Al react with the 6 moles of $H_2O$

0.22 moles of Al react with $\frac{6}{2}\times 0.22=0.66moles$ of $H_2O$

At STP, 1 mole contains 22.4 L volume

As, 1 mole of $H_2O$ contains 22.4 L volume of $H_2O$

0.66 moles of $H_2O$ contains $(22.4)\times (0.66)=14.784L$ volume of $H_2O$

Therefore, the volume of $H_2O$ is 14.784 L.

8 0

3 years ago

A certain second-order reaction (B→products) has a rate constant of 1.30×10−3 M−1⋅s−1 at 27 ∘C and an initial half-life of 224 s

soldier1979 [14.2K]

Answer:

$\large\boxed{\large\boxed{0.291M}}$

Explanation:

By definition one half-life is the time to reduce the initial concentration to half.

For a second order reaction the rate law equations are:

$\dfrac{d[B]}{dt}=-k[B]^2$

$\dfrac{1}{[B]}=\dfrac{1}{[B]_0}+kt$

The half-life equation is:

$t_{1/2}=\dfrac{1}{k[A]_0}$

Thus, substitute the rate constant $1.30\times 10^{-3}M^{-1}\cdot s^{-1}$ and the half-life time 224s to find [A]₀:

$224s=\dfrac{1}{1.30\times10^{-3}M^{-1}\cdot s^{-1}[A]_0}$

$[A]_o=0.291M$

7 0

4 years ago

What is the mass of mole of calcium carbonate

Minchanka [31]

What is the mass of mole of calcium carbonate

100.0869 g/mol

3 0

3 years ago

Find the zeros of the quadratic equation f(x)= 6x²-3, and verify the relation between its zeros and coefficients.

pishuonlain [190]

Answer:

f(x) = 6x²-3

f(x) = 0

6x²-3 = 0

6x² = 3

x² = 3/6

x² = 1/2

x = 1/√2 , -1/√2

Roots of f(x) = 1/√2 , -1/√2

Verification = (i) 6(1/√2)² - 3

= 6(1/2) - 3

= 3-3

= 0

(ii) 6(-1/√2)² - 3

= 6(1/2) - 3

= 3-3

= 0

5 0

3 years ago

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Name this structure ​

Name this structure