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Viktor [21]
2 years ago
13

A 10 kg bowling ball is lifted from the ground to a height of 1 meter. Assuming the bowling alley is on Earth, which type of pot

ential energy is stored in a ball and why? Class 6
Physics
1 answer:
kap26 [50]2 years ago
6 0

gravitational potential energy because the ball move towards the earth and to balance the weight of the ball so it moves in the right direction

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What happens when electrical energy is used to power stereo speakers? A. Energy is neither lost nor gained as electrical energy
Viktor [21]

Since energy can neither be created nor destroyed and it just changes from one form to another...so... A. Energy is neither lost nor gained as electrical energy is transformed into the energy of sound.

8 0
3 years ago
Which of the following are true statements? A. Like charges repel B. Unlike charges repel C. Unlike charges attract or D. Charge
Brums [2.3K]

Answer: The correct answers are (A) and (C).

Explanation:

The expression from electrostatic force is as follows;

F=\frac{kq_{1}q_{1}}{r^{2} }

Here, F is the electrostatic force, k is constant, r is the distance between the charges and q_{1},q_{1} are the charges.

The electrostatic force follows inverse square law. It is inversely proportional to the square of the distance between the charges. It is directly proportional to the product of the charges.

Like charges repel each other. There is a force of electrostatic repulsion between the like charges. Unlike charges attract each other. There is a force of electrostatic attraction between unlike charges.

The charges are induced on the neutral object when it is placed nearby the charged object without actually touching it.

Therefore, the true statements from the given options are as follows;

Like charges repel.

Unlike charges attract.

7 0
3 years ago
Can someone plz help me with this
Elena-2011 [213]
1st Law: Objects that are in motion tend to stay in motion. This motion can change with external forces. 

<span>If you were to stop pedaling on bike while in motion, you will notice that you will keep moving. This is because a moving body (you) has inertia. If there wasn't any friction between the tires and the ground, between the axles and wheel, any air resistance, or any other force that acts against you, then you could be coasting indefinitely! </span>

<span>2nd Law: Force is equal to the mass times acceleration. </span>

<span>When you pedal, you are applying a force onto the pedal. This force is then translated through tension to apply torque onto the wheel. Turning the wheel will make you accelerate in the lateral direction. </span>

<span>3rd Law: For every action, there is an equal and opposite reaction. </span>

<span>Without this, you could pedal and pedal, but you will be not go anywhere! It is essentially the friction between the tires and the ground that propels you forward. If the ground did not apply to the tire the same amount of force that the tire was applying to the ground, the tire would not "catch" and no friction would be applied. And if there was no third law, the weight of you and your bike would "sink" into the ground because the ground would not be applying a normal force back onto you.

hope this helps and if you have any questions just hmu and ask :)</span>
3 0
3 years ago
A person's _____________ will change if they move from the Earth to the moon.
Dennis_Churaev [7]

A person's weight will change if they move from Earth to the moon.

<h3>Hope this helps, sorry if not tho</h3><h3>Do you want to go live on the moon?</h3>
7 0
3 years ago
A tank having a volume of 0.85 m 3 initially contains water as a two-phase liquid-vapor mixture at 260 o C and a quality of 0.7.
Keith_Richards [23]

Answer:=14,160 kJ

Explanation: Let m1 and m2 be the initial and final amounts of mass within the tank, respectively. The steam properties are listed in the table below

Specific Internal SpecificTemp Pressure Volume Energy Enthalpy Quality Phase

C MPa m^3/kg kJ/kg kJ/kg

1 260 4.689 0.02993 2158 2298 0.7 Liquid Vapor Mixture

2 260 4.689 0.0422 2599 2797 1 Saturated Vapor

The mass initially contained in the tank is m1 = V/v1

m1 =0.85 m^3 /0.02993 m^3 /kg

= 28.4 kg

The mass finally contained in the tank is

m2 =V2/v

= 0.85 m^3 /0.0422 m^3 /kg

= 20.14 kg

The heat transfer is then

Qcv = m2u2 − m1u1 − he(m2 − m1)

Qcv = (20.14)(2599) − (28.4)(2158) − (2797)(20.14 − 28.4) = 14,160 kJ

4 0
3 years ago
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