Answer:
1. Covalent Bond
2. Ionic Bond
Explanation:
Covalent bonds are defined as the bond in which sharing of electrons takes place between atoms. The sharing of electrons is in equal number so that it form a stable balance of attraction and repulsion between atoms. In the given example of CO2 (first image) oxygen is sharing equal number of electrons with carbon to form a stable bond called covalent bond.
Ionic bonds are formed when valence electrons are transferred to other atoms and form oppositely charged ions. In ionic bond formation, the atoms that gain electrons become negatively charged and the atoms that loses electrons become positively charged. In the given example of Ca Cl2, Ca is also giving its 2 valence electrons to each Cl and there is no stable balance of attraction and repulsion between atoms.
Hence, the correct answer is:
1. Covalent Bond
2. Ionic Bond
Answer:
98.6 g/mol.
Explanation:
Equation of the reaction
HX + NaOH--> NaX + H2O
Number of moles = molar concentration × volume
= 0.095 × 0.03
= 0.00285 moles
By stoichiometry, 1 mole of HX reacted with 1 mole of NaOH. Therefore, number of moles of HX = 0.00285 moles.
Molar mass = mass ÷ number of moles
= 0.281 ÷ 0.00285
= 98.6 g/mol.
I would say to double the weight
Answer:
Explanation:
A. White blood cells have many lysosomes because they need to produce a lot of glucose and oxygen.
Lysosomes are found in all animal cells, but are most numerous in disease-fighting cells, such as white blood cells. This is because white blood cells must digest more material than most other types of cells in their quest to battle bacteria, viruses, and other foreign intruders.
Answer:
See Explanation
Explanation:
In the first case, when potassium iodide is added to an aqueous bromine solution, a chemical reaction occurs as follows;
Br2(l) + 2 KI(aq) = 2 KBr(aq) + I2(l)
This reaction produces iodine solution which is brown in colour.
Secondly, when potassium iodide is added to aqueous chlorine solution, the following reaction occurs;
2KI(aq) + Cl2(l)→ 2KCl(aq) + I2 (l)
This reaction also yields iodine solution which is brown in colour.
KI(aq) + I2(l) -------->K^+(aq) + I3^-(aq)
The I3^-(aq) solution appears brown at high concentrations.
