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Oliga [24]
2 years ago
9

A neutral solid metal sphere of radius 0.1 m is at the origin, polarized by a point charge of 2 × 10−8 C at location m. At locat

ion m, what is the electric field contributed by the polarization charges on the surface of the metal sphere? (Express your answer in vector form.)
Physics
1 answer:
liraira [26]2 years ago
6 0

Answer: E = 1.8 *10 ^{4} N

Explanation: The formulae for intensity of an electric field of a solid metal sphere relative to a point is given below

E =\frac{Kq}{r^{2} } r

where  k=9* 10^{9}N/m^{2}, q=2 *10 ^{-8} c , r = 0.1m r = is the position vector of the charge.

it has been stated in the question that the charge is placed at the center thus it has no position vector.

E=\frac{9 * 10^{9}* 2* 10^{-8}  }{0.1^{2} }\\ =\frac{18* 10^{1} }{0.01} \\=\frac{18* 10^{1} }{1 *10^{-2} } = 1.8*10^{4} N

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Answer:

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Explanation:

we know that:

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Replacing values, we get:

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