PLS SOMEONE HELP ME ASAP

Can anyone help me if i dont get my grade up i wont get to go to my vollyball games

Alexxandr [17]

Answer:

x = 30

Step-by-step explanation:

$\frac{3}{5}$ (30) + $\frac{1}{3}$ (30) = 28

$\frac{3}{5}$ (30) = 18

$\frac{1}{3}$ (30) = 10

18 + 10 = 28

8 0

2 years ago

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Use substitution. What is the solution to the system of equations? Use the drop-down menus to explain your answer.

Hoochie [10]

Answer:

The system of equations has one solution. The two equations are intersecting lines.

Step-by-step explanation:

if you want to use the substitution method, you would have to plug in y for 12x+2 in the second equation.

2(12x+2)=x+4

next, you have to distribute

24x+4=x+4

subtract 24x from each side

4=-23x+4

subtract 4 from each side

0=23x

divide each side by 23

x=0

now, plug in 0 to one equation.

y=12(0)+2

y=2

the lines intersect at one point, (0,2)

7 0

2 years ago

A professor has recorded exam grades for 10 students in his class, but one of the grades is no longer readable. If the mean sco

Nostrana [21]

Answer:

unreadable score = 35

Step-by-step explanation:

We are trying to find the score of one exam that is no longer readable, let's give that score the name "x". we can also give the addition of the rest of 9 readable s scores the letter "R".

There are two things we know, and for which we are going to create equations containing the unknowns "x", and "R":

1) The mean score of ALL exams (including the unreadable one) is 80

so the equation to represent this statement is:

mean of ALL exams = 80

By writing the mean of ALL scores (as the total of all scores added including "x") we can re-write the equation as:

$\frac{R+x}{10} =80$

since the mean is the addition of all values divided the total number of exams.

in a similar way we can write what the mean of just the readable exams is:

$\frac{R}{9} = 85\\$ (notice that this time we don't include the grade x in the addition, and we divide by 9 instead of 10 because only 9 exams are being considered for this mean.

Based on the equation above, we can find what "R" is by multiplying both sides by 9:

$\frac{R}{9} = 85\\R=85*9= 765$

Therefore we can now use this value of R in the very first equation we created, and solve for "x":

$\frac{R+x}{10} =80\\\frac{765+x}{10} =80\\765+x=80*10=800\\765+x=800\\x=800-765=35$

4 0

2 years ago

16x4<br> what is the answer?

Viefleur [7K]

Answer:

64

Step-by-step explanation:

8 0

2 years ago

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The sum of three consecutive integers is 48. What are the three numbers?

Alinara [238K]

What three consecutive integers have a sum of 48? Which means that the first number is 15, the second number is 15 + 1 and the third number is 15 + 2. Therefore, three consecutive integers that add up to 48 are 15, 16, and 17.

7 0

2 years ago