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Finger [1]
3 years ago
8

PLS SOMEONE HELP ME ASAP

Mathematics
1 answer:
adoni [48]3 years ago
5 0

circumference/diameter = 3.14159

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Drag each number to the correct location on the table.
ASHA 777 [7]

Answer:

\text{Rational number} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{ Irrational number}

          3\sqrt{25}  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \sqrt{141}\\\\\sqrt{256} \\\\1. \overline{ 1625} \\\\\frac{-11}{151}

Step-by-step explanation:

Since we believe it  

The number sequence is that those which can be described as \frac{p}{q} and that is not ending and recurring.  Figures that are unreasonable are also the ones, that are not \frac{p}{q} and therefore are non-ending, non-recurring.  

The number sequence is 3\sqrt{25} = 3 \times 5 = 15

Rational amount since it is classified as \frac{p}{q}  .\frac{-11}{151} is really a rational number.  

1.\overline{1.625} is a real function, since it does not end but repeats it.  

The rational number \sqrt {256} = 16

Unreasonable number \sqrt{141}.

7 0
3 years ago
Read 2 more answers
Find the solutions for 6x^2 -7x-20=0
Ugo [173]

Answer:

x=5/2, x=-4/3

Step-by-step explanation:

4 0
3 years ago
Navin signed up for a gym membership. The cost was $125 plus $20 each
Lisa [10]

Answer:

a) the initial value is $125, and it represents the cost Navin has to pay in the beginning

b) the rate of change is  $20 per month, and it represents the cost he has to pay per month

c) linear; the equation for it is y = 20x + 125

d) The rate of change is constant because each month, Navin always has to pay $20.

e) This is <u>partial variation</u> because the equation y = 20x + 125 doesn't follow y = kx

Have a lovely rest of your day/night, and good luck with your assignments! ♡

6 0
2 years ago
7mm 13mm 4mm surface area
kogti [31]
342=2[(7*13)+(7*4)+(13*4)]
3 0
3 years ago
G(x)=(cosθsinθ)^4 what's the differential
natulia [17]

Answer:

sin²2θ. (cos θ sin θ). cos 2θ

Step-by-step explanation:

finding g'(x)

g'(x)

  • (x^n)' = nx^(n -1)

= 4 (cosθsinθ)³ . { cosθ. (sinθ)' + sinθ. (cosθ)' }

  • (cosθ)' = - sinθ
  • (sinθ)' = cosθ

= 4 (cosθsinθ)³ { cosθ. cos θ + sinθ.(-sin θ)}

= 4 (cosθsinθ)³{ cos²θ - sin²θ}

  • cos²θ - sin²θ = cos 2θ
  • 2sinθ cosθ = sin 2θ

= (4 cosθ sinθ)². (cosθ sinθ). { cos²θ - sin²θ}

= <u>sin²2θ. (cos θ sin θ). cos 2θ</u>

4 0
3 years ago
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