T k = 15 + 273 = 288 K
4.6 / 13 => 0.353 atm
0.50 / 0.10 => 5 L
<span>(15 + 273) K x (13 atm / 7.6 atm) x (0.50 L / 0.10 L)
</span>
<span>= </span>2463.15 K
<span>hope this helps!</span>
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Answer:
The C14 would be found in Glyceraldehyde-3-Phosphate, and the O18 would also be found in the same molecule
Explanation:
Isotopic labeling is a common method for deducing reaction mechanism in chemistry.
In photosynthesis, the oxygen in the found in Glyceraldehyde-3-Phosphate comes from the carbon dioxide, This is also finally found in the glucose produced at the end of the cycle.
The oxygen in water is released into the atmosphere as the oxygen molecule.
Therefore, the C14 would be found in Glyceraldehyde-3-Phosphate, and the O18 would also be found in the same molecule.
Metals-
-Shiny surface
-good conductor of electricity
-good conductor of heat
-malleable
Non- Metals-
-dull surface
-poor conductor of heat
-poor conductor of electricity
-brittle