Answer:
An asteroid moving at a constant speed through space.
Explanation:
Answer:
Momentum, p = 23250 kg m/s
Explanation:
Given that
Mass of a car, m = 1550 kg
Speed pf car, v = 15 m/s
We need to find the momentum of the car. The formula for the momentum of an object is given by :
p = mv
Substituting all the values in the above formula
p = 1550 kg × 15 m/s
p = 23250 kg m/s
So, the momentum of the car is 23250 kg m/s.
Acceleration=(change in speed)/(time for the change). 43/0.28 = 153.6 m/s^2.
A Post-and-lintel is a system that uses vertical posts which are separated to
support a horizontal beam.
A Post-and-lintel system is commonly used in architecture and involves the
system where horizontal structures are held by vertical ones with the
presence of spaces between them.
In this scenario, we were told the system uses vertical posts which are
separated to support a horizontal beam which makes Post-and-lintel the
most appropriate choice.
Read more on brainly.com/question/8777125
Answer:
0.423m
Explanation:
Conversion to metric unit
d = 4.8 cm = 0.048m
Let water density be 
Let gravitational acceleration g = 9.8 m/s2
Let x (m) be the length that the spring is stretched in equilibrium, x is also the length of the cylinder that is submerged in water since originally at a non-stretching position, the cylinder barely touches the water surface.
Now that the system is in equilibrium, the spring force and buoyancy force must equal to the gravity force of the cylinder. We have the following force equation:

Where
N is the spring force,
is the buoyancy force, which equals to the weight
of the water displaced by the submerged portion of the cylinder, which is the product of water density
, submerged volume
and gravitational constant g. W = mg is the weight of the metal cylinder.

The submerged volume would be the product of cross-section area and the submerged length x

Plug that into our force equation and we have


