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Alex73 [517]
2 years ago
7

Một nười thả 420g chì ở nhiệt độ 100°C và 260g nước ở nhiệt độ 58°C làm cho nước nóng lên tới 60°C . Cho nhiệt dung riêng của nư

ớc là 4200J/kg.K và bảo qua sự hao phí nhiệt ra môi trường bên ngoài . Hãy tính :
a) Nhiệt độ của chì khi có cân bằng nhiệt

b) Nhiệt lượng nước đã thu vào

c) Nhiệt dung riêng của chì

d) Nếu muốn nước và chì nóng tới nhiệt độ 75°C thì cần thêm vào một lượng chì ở nhiệt độ 150°C là bao nhiêu ?
Physics
1 answer:
vlabodo [156]2 years ago
6 0
Hey what language is this?
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Which geologic feature most likely be represented by contour lines drawn far apart from one another?
andrey2020 [161]

Answer;

A plain

Explanation;

A contour line connects points of the same elevation. Contour lines are usually curves. Closed contours represent hills.

Contour lines can not cross since they represent different elevations. A contour interval is the difference in elevation between one contour and an adjacent contour.

5 0
3 years ago
A 15 n force directed to the west acts on an object for 3.0 seconds, what is the change in momentum of the object?
pickupchik [31]
By definition we have that
 force=dP/dt,
 where
 p is momentum
 so
 <span>momentum is force*time
 p= 15*3 = 45 Ns , west.
 </span><span>the change in momentum of the object is 45 N.s</span>
7 0
3 years ago
An object of mass 20 kg is raised vertically through a distance of 8 m above ground level. If g = 10 m/s2, what is the gravitati
IgorC [24]

2400joules

Explanation:

P.E

m= 20kg h=8m g=10m

P.E= 20×8×10

=2400joules

6 0
2 years ago
Can someone help me?
Setler [38]

Answer: (1, 30), (2,10), (3,40), (4,20)

Explanation:

4 0
2 years ago
The pressure P (in kilopascals), volume V (in liters), and temperature T (in kelvins) of a mole of an ideal gas are related by t
stich3 [128]

Answer:

\dfrac{dV}{dt} = -0.466 m^3/s

Explanation:

given,

P (in kilo pascals),         volume V (in liters),        temperature T (in kelvins)

P V = 8.31 T

Rate of increase the temperature =  0.1 K/s

temperature = 285 K

Pressure = 18 kPa

increasing at the rate of 0.07 k Pa/s

Rate at which volume is changing = ?

V = 8.31 \dfrac{T}{P}

\dfrac{dV}{dt} = 8.31 \dfrac{P\dfrac{dT}{dt}-T\dfrac{dP}{dt}}{P^2}

\dfrac{dV}{dt} = 8.31 \dfrac{18 \times 0.1-285\times 0.07}{18^2}

\dfrac{dV}{dt} = 8.31 \dfrac{-18.15}{324}

\dfrac{dV}{dt} = -0.466 m^3/s

7 0
3 years ago
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