Consider two identical insulated metal spheres, A and B. Sphere A initially has a charge of -6.0 units and sphere B initially ha
1 answer:
Answer:
<em>-2 units of charge</em>
Explanation:
charge on A = Qa = -6 units
charge on B = Qb = 2 units
if the spheres are brought in contact with each other, the resultant charge will be evenly distributed on the spheres when they are finally separated.
charge on each sphere will be =
charge on each sphere = =
= <em>-2 units of charge</em>
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Answer: Length axis f= 114.3 Hz, Width axis f=228.67 Hz
Explanation:
We are given that,
Length of tub= 1.5 m
Width of tub= 0.75 m
Sound speed= 343 m/s
Now, we are also given shower is closed.
So, frequency is given as:
f=
For length axis
Put v= 343 m/s, m=1 and L=1.5 m
f= 1 *
f= 114.3 Hz
For next resonant frequency, m=2
f= 2*
f= 228.67
For width axis
Put v= 343 m/s, m=1 and L= 0.75 m
f= 1*
f= 228.67 Hz
For next frequency, m=2
f= 2*
f= 457.34 Hz
Answer:
The maximum speed of the wing tip is 1.25 m/s
Explanation:
In simple harmonic motion, the body experiences a restoring force whose magnitude is directly proportional to the distance from its mean position and its direction is towards the mean position.
The speed in the case of simple harmonic motion is given by the equation :
v = Aωsinωt
Here A is maximum displacement, t is time and ω is the angular frequency of oscillation.
For maximum speed, sinωt = 1 . So, the above equation becomes:
v = Aω
But, ω = 2πf , here f is the frequency of oscillation. So,
v = A x 2πf .....(1)
In this problem,
Frequency of oscillation, f = 40 Hz
Total distance between the upper and lower limits of motion of wing tip is equal to the twice of maximum displacement of the wing tip from the equilibrium position, i.e. ,
2 x A = 1 cm
A = 0.5 cm = 0.5 x 10⁻² m
Substitute the value of f and A in equation (1).
v = 1.25 m/s