The total potential energy associated with the jumper at the end of his fall is 90,000 J.
The given parameters;
- <em>mass of the jumper, m = 51 kg</em>
- <em>height of the bridge. h = 321 m</em>
- <em>spring constant of the cord, k = 32 N/m</em>
- <em>extension of the cord, x = 179 m - 104 m = 75 m</em>
The total potential energy associated with the jumper at the end of his fall is calculated as follows;
U = ¹/₂kx² + mgΔh
where;
<em>Δh is the change in height after falling </em>
U = ¹/₂(32)(75)² + (51)(9.8)(0)
U = 90,000 J
Thus, the total potential energy associated with the jumper at the end of his fall is 90,000 J.
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Answer:
( 1000 × 4 = 4,000) (800×3= 2400) (800×2=1600) the answer is 1600 hope it helps
Gravitational potential energy can be calculated using the formula:

Where:
PEgrav = Gravitational potential energy
m= mass
g = acceleration due to gravity
h = height
On Earth acceleration due to gravity is a constant 9.8 but since the scenario is on Mars, the pull of gravity is different. In this case, it is 3.7, so we will use that for g.
So put in what you know and solve for what you don't know.
m = 10kg
g = 3.7m/s^2
h = 1m
So we put that in and solve it.


Answer: 1. higher than it was before they started running
Explanation: As the vacationers run towards the back(stern) of the ship the exerting more pressure against the pressure exerted by the wave supporting the moving ship,the pressure exerted on the moving ship will be increased, leading to a slight increase in the speed of the ship compared to the speed before they started running towards the back(stern) of the ship.
Answer:
<em>The power generated is = 5.33×10⁸ Watt. </em>
Explanation:
Power: Power can be defined as the time rate of doing work. The S.I unit of power is <em>Watt(W).</em>
<em>Mathematically,</em>
<em>Power (P) = Work done/time or Energy/time</em>
P = mgh/t............................... Equation 1
P = δgh............................. Equation 2
Where δ = fall rate, g = acceleration due to gravity, h = height.
<em>Given: </em>δ = 1.1×10⁶ kg/s, h = 49.4 m g = 9.81 m/s²
Substituting these values into equation 2
P = 1.1×10⁶×49.4×9.81
P = 533.08×10⁶
<em>P = 5.33×10⁸ Watt.</em>
<em>Thus the power generated is = 5.33×10⁸ Watt. </em>