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3 years ago

7

How can seismographs be used to predict hurricane intensity?

1 answer:

nikdorinn [45]3 years ago

6 0

Answer: The earth is a noisy place. Seismometers, which measure ground movements to detect earthquakes, volcanic eruptions, and manmade explosives, are constantly recording smaller vibrations caused by ocean waves, rushing rivers, and industrial activity.

Explanation:

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To determine if an object is in motion, you must use a __________. Question 1 options: Moving object Living thing Frame of Refer

Lubov Fominskaja [6]

Answer: moving object :)

Explanation:

8 0

3 years ago

All of the following events can trigger an adaptive radiation except _____.

stellarik [79]

The answer would be
A. an unusual event splitting a habitat, such as a severe hurricane

7 0

4 years ago

A bicycle tire pump has a piston with area 0.43 In2. If a person exerts a force of 16 lb on the piston while Inflating a tire, w

Gelneren [198K]

Answer:

The pressure produced on the air in the pump is 37.209 pounds per square inch.

Explanation:

By definition, the pressure is the force exerted on the piston divided by its area. Given that, force is distributed uniformly on the piston area, the formula to determine the pressure is:

$p = \frac{F}{A}$

Where:

$p$ - Pressure, measured in pounds per square inch.

$F$ - Force exerted on the piston, measured in pounds.

$A$ - Piston area, measured in square inches.

If $F = 16\,lb$ and $A = 0.43\,in^{2}$ , the pressure produced on the air in the pump is:

$p = \frac{16\,lb}{0.43\,in^{2}}$

$p = 37.209\,psi$

The pressure produced on the air in the pump is 37.209 pounds per square inch.

8 0

3 years ago

Assume that, as the battery wears out, the voltage decreases at 0.03 volts per second and, as the resistor heats up, the resista

liraira [26]

Answer:

$\frac{dI}{dt} =-3*10^-^4amps/sec$

Explanation:

From the question we are told that

Voltage decreases at $\frac{dv}{dt} =-0.03volts/sec$

Resistance increase at $\frac{dR}{dt}=0.02ohms /sec$

Resistance at $R=100ohms$

Current at $I=0.02amps$

Generally the equation for ohms law is mathematically represented as

$V=IR$

Therefore

$\frac{dV}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}$

Generally making $\frac{dI}{dt}$ subject of the formula in the above equation mathematically gives

$\frac{dV}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}$

$R\frac{dI}{dt} = \frac{dV}{dt} -I\frac{dR}{dt}$

$\frac{dI}{dt} =\frac{1}{R} (\frac{dV}{dt} -I\frac{dR}{dt})$

Therefore

$\frac{dI}{dt} =\frac{1}{100}((-0.03) -(0.02)*(0.02))$

Generally it is given that the change in current is

$\frac{dI}{dt} =-3*10^-^4amps/sec$

8 0

3 years ago

Energy that is associated with the position or composition of an object is called

Pani-rosa [81]

That is potential energy.

4 0

3 years ago