Answer:
(a) Position Vectors V₁= -2î km, V₂=5î km
(b) Displacement Δx=7 km
Explanation:
Given data
Distance=2 km west at t=0
Distance=5 km east at t=6 min
Positive x is the east direction
To find
(a)Car position vector at given times
(b)Displacement between 0 to 6.0 min
Solution
For Part (a) car position vector at given times
At t=0 the distance=2 km west so conclude that x₁=-2 because it is in negative side So vector V₁
V₁= -2î km
At t=6.0 the distance=5 km east so conclude that x₂=5 because it is in positive side So vector V₂
V₂=5î km
For (b) displacement between 0 to 6.0 min
According to following mathematical law we can conclude that
Δx=x₂-x₁
Δx=5-(-2)km
Δx=7 km
Explanation:
can u please translate it to english language. I can't understand.
Answer:
The recurve bows
Explanation:Vote brainliest plz
32miles/hr
Explanation:
Given parameters:
Distance 1 = 60miles
Time 1 = 2hrs
Distance 2 = 68miles
Time 2 = 2hrs
Unknown:
Average speed of the car = ?
Solution:
Average speed is the total distance covered in a particular duration of time.
Average speed = 
Total time taken = time 1 + time 2 = 2hrs + 2hrs = 4hrs
Total distance = distance 1 + distance 2 = 60miles + 68miles = 128miles
Average speed =
= 32miles/hr
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Answer:
Under assumption that all food energy that needs the horse is transformed into work, then the horse needs approximately 3 megajoules of food energy to work for 1 hour.
Explanation:
Since horse is working steadily, the power experimented by the horse (
), measured in watts, is at constant rate. Then, the work needed by the horse (
), measured in joules, is equal to that power multiplied by time (
), measured in seconds. That is:
(1)
If we know that
and
, then the work needed for the horse is:



Under assumption that all food energy that needs the horse is transformed into work, then the horse needs approximately 3 megajoules of food energy to work for 1 hour.