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scoray [572]
3 years ago
7

On a spring scale that measures force, a reading shows the force of an object to be about half way between 0 N and 1 N. Which of

the following would be the most accurate measurement for the force?
49.0 N
0.49 N
0.049 N
4.90 N
Physics
1 answer:
deff fn [24]3 years ago
7 0
0.49 N
On a spring scale that measures force, a reading shows the force of an object to be about half way between 0 N and 1 N. 0. 49 Newton is the most accurate measurement for the force. If we cluster the number values of 0 N to 1 N It would be 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0 N. These numbers indicate the micro intervals of 0-1. It cannot be the other given because the other values are either higher or lower which exceeds the 0-1 scale. Observe.



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Which of The following are classiFcatons describing how rock and oTher maTerial movedownslope?a. Fall, b. slide, c. slump, d. cr
nlexa [21]

Answer:

correct answer is Fall slide, slump, creep, flow

Explanation:

solution

we know that Movement of particle under the influence of gravity

so rock and other material move down as gravity.

first rock particle fall down because falls occur very rapidly with high slope after that they slide on the slope and after sliding they slump and it occurs when the rupture surface is curved after slump process they creep.  

after creeping, it can flow particle as it occurs slowly with the low slope with water.

so correct answer is Fall slide, slump, creep, flow

7 0
3 years ago
Describe the difference between the velocity graph made walking at a steady rate and the velocity graph made at an increasing ra
levacccp [35]

Answer:

The difference between the velocity graph made walking at a steady rate means that its the same value in time, that means there's no slope on the graph, so its acceleration is 0

On the other hand, if the velocity is increasing with time, the slope of the graph becomes positive, which means that the acceleration of the particle is positive.

8 0
3 years ago
(1 point) A pilot flies in a straight path for 1 hour and 30 min. She then makes a course correction, heading 10 degrees to the
kati45 [8]

Answer:

The pilot is 2214.22 miles from her starting position

Explanation:

Since the pilot is traveling at a constant speed of 635 mph, the total distance traveled can be easily found as follows:

1stleg: d_{1} = 1.5*635 = 952.5 mi\\2ndleg: d_{2} = 2*635 = 1270 mi

There was a 10 degrees deviation, so the angle between the trajectory of both legs is 170 degrees.

The distance we need to find is that from the start of the first leg to the end of the second leg, those three distances form a triangle and since the side we're interested in is opposite to the 170 degrees angle, we can determine its length by the law of cosines:

d_{3}^{2} =d_{1}^{2} + d_{2}^{2} -2*d_{1}*d_{2}*cos(170)\\d_{3}^{2} =952.5^{2} + 1270^{2} -2*952.5*1270*cos(170)\\d_{3}=2214.22mi

The pilot is 2214.22 miles from her starting position

8 0
3 years ago
The two forces in each pair can either both act on the same body or they can act on different bodies. The two forces in each pai
Marrrta [24]

Answer:

The correct answer in which peer forces each act in a different body

Explanation:

Newton's law of action and reaction states that the two forces have equal magnitude, but in the opposite direction, each acting on a body. Which creates acceleration in these, if they act in the same body it would be canceled so there would be no movement.

The correct answer in which peer forces each act in a different body

6 0
3 years ago
A car of 900 kg mass is moving at the velocity of 60 km/hr. It is brought into rest at 50 meter distance by applying a brake. No
kozerog [31]

Answer: -2502N

Explanation:

(V_2)^2=(V_1)^2+2ad

where;

V_2 = final velocity = 0

V_1 = initial velocity = 60 km/h = 16.67 m/s

a = acceleration

d = distance

First all of, because acceleration is given in m/s and not km/h, you need to convert 60km/h to m/s. Our conversion factors here are 1km = 1000m and 1h = 3600s

60km/h(\frac{1000m}{1km} )(\frac{1h}{3600s} )=16.67m/s

Solve for a;

(V_2)^2=(V_1)^2+2ad

Begin by subtracting (V_1)^2

(V_2)^2-(V_1)^2=2ad

Divide by 2d

\frac{(V_2)^2-(V_1)^2}{2d} =a

Now plug in your values:

a=\frac{(0)^2-(16.67 m/s)^2}{2(50m)}

a=\frac{0-277.89m^2/s^2}{100m}

a=-2.78m/s

If you're wondering why I calculated acceleration first is because in order to find force, we need 2 things: mass and acceleration.

F=ma

m = mass = 900kg

a = acceleration = -2.78m/s

F=(900kg)(-2.78m/s)\\F=-2502N

It's negative because the force has to be applied in the opposite direction that the car is moving.

8 0
3 years ago
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