Explanation:
Each resistor has a resistance of R.
In the first problem, each row of three resistors in series has a resistance or 3R.
A₂ = 4A, so the voltage drop across the rows is:
V = IR
V = (4)(3R)
V = 12R
The voltage drop equals the voltage gain (Kirchoff's voltage law). The battery has a voltage of 9V, so:
9 = 12R
R = 0.75 Ω
The three rows are in parallel with each other, so the total resistance is:
∑R = (1/(3R) + 1/(3R) + 1/(3R))⁻¹
∑R = R
∑R = 0.75 Ω
The current A₁ can be found with Ohm's law:
V = IR
9 = (A₁) (0.75)
A₁ = 12 A
Using Ohm's law to find V₁, V₂, and V₃:
V = IR
V₁ = (4)(0.75)
V₁ = 3V
V₂ = (4)(2×0.75)
V₂ = 6 V
V₃ = (4)(3×0.75)
V₃ = 9 V
In the second problem, all the resistors are in series. So the total resistance is:
∑R = 8R
The battery voltage is 16V, and A₂ = 6A. So using Ohm's law:
V = IR
16 = (6)(8R)
R = 1/3 Ω
Since there's only one loop, the current is the same at all points. So A₁ = A₂ = 6A.
Using Ohm's law to find each voltage:
V = IR
V₁ = (6)(1/3)
V₁ = 2V
V₂ = (6)(2×1/3)
V₂ = 4 V
V₃ = (6)(4×1/3)
V₃ = 8 V
V₄ = (6)(2×1/3)
V₄ = 4 V
Answer:
B - Divide Speed and Distance
Explanation:
Hope it helps!!
:D
Answer:
Explanation:
a )
We shall apply the concept of impulse .
Impulse = force x time = change in momentum
= 5 x 4 = 2 ( V - 3 ) , where V is final velocity of the object
20 = 2V - 6
V = 13 m /s
b )
Impulse applied = - 7 x 4 = - 28 kg m/s ( negative as direction of force is opposite motion )
If v be the final velocity
2 x 3 - 28 = 2 v ( initial momentum - change in momentum = final momentum )
- 22 = 2v
v = - 11 m /s
object will move with 11 m /s in opposite direction .
Answer:
255 metres
Explanation:
The answer to thi question is actually quite simple. Since the car goes for 3.4 seconds, and it goes 75 metres every second, the answer is just 3.4 multiplied by 75 Metres.