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Neporo4naja [7]
3 years ago
14

Inertia is responsible for :

Physics
2 answers:
DENIUS [597]3 years ago
8 0
B. the reason we must wear seat belts
Arisa [49]3 years ago
8 0
B) we need seat belts to keep us in the car just in case a car breaks suddenly or hits another.

Remember— an object in motion will remain in motion until acted on be another outside force acts upon it
In this case the seat belt is the outside force.

An object will remain at rest until an outside force acts upon it.

Hope this helps!
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Help quick
Yanka [14]

C it reduces the amount of useful work done on objects move it up the ramp

8 0
3 years ago
What factors affect the gravitational pull of two massive objects?​
Mrrafil [7]

Answer:Mass and distance

Explanation:The strength of the gravitational force between two objects depends on two factors, mass and distance. the force of gravity the masses exert on each other. If one of the masses is doubled, the force of gravity between the objects is doubled. increases, the force of gravity decreases.

Hope this helps!!

3 0
3 years ago
A very long straight current-carrying wire produces a magnetic field of 25 µT at a distance d from the wire. How far will the ma
daser333 [38]

The magnetic field strength of a very long current-carrying wire is proportional to the inverse of the distance from the wire. The farther you go from the wire, the weaker the magnetic field becomes.

B ∝ 1/d

B = magnetic field strength, d = distance from wire

Calculate the scaling factor for d required to change B from 25μT to 2.8μT:

2.8μT/25μT = 1/k

k = 8.9

You must go to a distance of 8.9d to observe a magnetic field strength of 2.8μT

6 0
3 years ago
according to newtons first law of motion, what will an object in motion do when no external force acts on it?​
shutvik [7]

Answer:

The object will not move.

Explanation:

If nothing pushes against it it will not move. If its not on a slant it will not move.

4 0
3 years ago
Read 2 more answers
A long, rigid conductor, lying along the x-axis, carries a current of 7.0 A in the negative direction. A magnetic field B is pre
Alisiya [41]

Answer:

0.546 \hat k

Explanation:

From the given information:

The force on a given current-carrying conductor is:

F = I ( \L  \limits ^ {\to } \times B ^{\to})\\ \\ dF = I(dL\limits ^ {\to } \times B ^{\to})

where the length usually in negative (x) direction can be computed as

\L ^ {\to }  = -x\hat i \\dL\limits ^ {\to }- dx\hat i

Now, taking the integral of the force between x = 1.0 m and x = 3.0 m to get the value of the force, we have:

\int dF = \int ^3_1 I ( dL^{\to} \times B ^{\to})

F = I \int^3_1 ( -dx \hat i ) \times ( 4.0 \hat i + 9.0 \ x^2 \hat j)

F = I \int^3_1  - 9.0x^2 \ dx \hat k

F = I  (9.0) \bigg [\dfrac{x^3}{3} \bigg ] ^3_1 \hat k

F = I  (9.0) \bigg [\dfrac{3^3}{3} - \dfrac{1^3}{3} \bigg ]  \hat k

where;

current I = 7.0 A

F = (7.0 \ A)  (9.0) \bigg [\dfrac{27}{3} - \dfrac{1}{3} \bigg ]  \hat k

F = (7.0 \ A)  (9.0) \bigg [\dfrac{26}{3} \bigg ]  \hat k

F = 546 × 10⁻³ T/mT \hat k

F = 0.546 \hat k

4 0
3 years ago
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