In order to balance both of the reactions you need to make sure that both sides of the reaction have the same number of atoms for each atom in order to follow conservation of mass.
KCl+F₂→KF+Cl₂
Notice how in the above reaction there are two chlorine atoms on the products side (right side) and only one atom of chlorine on the reactants side (left side). you want both the reactants and products side to have the same amount chlorine and to do this multiply KCl by 2. Fluorine however, has 2 atoms on the reactant side and 1 atom on the product side. to fix this multiply KF by 2. <span>Therefore the balanced reaction is: 2KCl+F₂→2KF+Cl₂
</span>notice how both sides of the reaction have equal numbers of each atom.
Mg+HCl→MgCl₂+H₂
the above reaction has 2 atoms of H on the products side and only 1 atom of H on the reactants side. That means you have to multiply HCl by 2. Now you have the equation Mg+2HCl→MgCl₂+H₂. As you can see now we have equal numbers of all the atoms on both sides which means that that is the balanced equation.
I hope this helps. Let me know if you have any further questions or need anything to be clarified.
Answer:
The answer to your question is: yield = 56.27%
Explanation:
Data
CH3CH2CH2CH2OH (l) → CH3 CH2CH2CH2Br
18.54 ml 1-butanol 15.65 g of 1-bromobutane
% yield = ?
density = 0.81 g/ml
MM = 74 g 1- butanol
MM = 137 g 1-bromobutane
Process
Calculate mass of 1- butanol
density = mass/volume
mass = density x volume
mass = 0.81 x 18.54
mass = 15.02 g of 1-butanol
Theoretical yield
74 g of 1- butanol ----------------- 137 g of 1-bromobutane
15.02 g of 1- butanol ------------- x
x = (15.02 x 137) / 74
x = 27.81 g of 1-bromobutane
% yield = experimental yield / theoretical yield x 100
% yield = 15.65 / 27.81 x 100
% yield = 56.28
Answer:Chemical reactions occur when chemical bonds between atoms are formed or broken. The substances that go into a chemical reaction are called the reactants, and the substances produced at the end of the reaction are known as the products.
Explanation:
Answer:
2.82 L
T₁ = 303 K
T₂ = 263 K
The final volume is smaller.
Explanation:
Step 1: Given data
- Initial temperature (T₁): 30 °C
- Initial volume (V₁): 3.25 L
- Final temperature (T₂): -10 °C
Step 2: Convert the temperatures to Kelvin
We will use the following expression.
K = °C + 273.15
T₁: K = 30°C + 273.15 = 303 K
T₂: K = -10°C + 273.15 = 263 K
Step 3: Calculate the final volume of the balloon
Assuming constant pressure and ideal behavior, we can calculate the final volume using Charles' law. Since the temperature is smaller, the volume must be smaller as well.
V₁/T₁ = V₂/T₂
V₂ = V₁ × T₂/T₁
V₂ = 3.25 L × 263 K/303 K = 2.82 L
1 mole C₆H₁₂O₆ ------------- 6 moles oxygen
3 moles C₆H₁₂O₆ ----------- X
X = (3×6)/1
X = 18 moles
