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3 years ago

8

The ions Cr3+ and O2- combine to form the ionic compound chromium oxide. In what proportions do these ions combine to produce a

neutral compound?

2 answers:

VMariaS [17]3 years ago

7 0

<span>Cr3+ O2- ; the formula is Cr2O3 ( criss cross)</span>

kramer3 years ago

6 0

Your answer for plato is 2:3

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A sample of chemical X is found to contain 5.0 grams of oxygen, 10.0 grams of carbon, and 20.0 grams of nitrogen. The law of def

frozen [14]

Answer: 75 grams sample of chemical X should contain 21.43 grams of carbon

Explanation: The law of definite proportion states that a given chemical compound always contains its component elements in fixed ratio.

From the question, chemical X contains 5.0 grams of oxygen, 10.0 grams of carbon, and 20.0 grams of nitrogen.

Sum up the masses

5.0g + 10.0g + 20.0g = 35.0g

This means, 10.0 grams of carbon are present in 35.0 grams of chemical X.

Now, to the determine the mass of carbon that 75 gram sample of chemical X should contain,

According to the law of definite proportion, the component elements of a given chemical compound are in fixed ratio. Therefore,

If 35.0g of chemical X contains 10.0g of carbon

Then, 75 g of chemical X will contain

(75 × 10) / 35 g

= 21.43 grams

Hence, 75 grams sample of chemical X should contain 21.43 grams of carbon.

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3 years ago

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What is the basic unit of all matter? O A. neutron O B. atom KDC. electron OD proton NUNE nucleus Reset Next

Salsk061 [2.6K]

Answer:

Atom

Explanation:

atom: The basic unit of matter; the smallest unit of an element, having all the characteristics of that element; consists of negatively-charged electrons and a positively-charged center called a nucleus.

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3 years ago

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50 mL of 0.1 M acetic acid is mixed with 50 mL of 0.1 M sodium acetate (the conjugate base). The Ka of acetic acid is approximat

trapecia [35]

Answer:

4.76

Explanation:

In this case, we have to start with the <u>buffer system</u>:

$CH_3COOH~->~CH_3COO^-~+~H^+$

We have an acid ( $CH_3COOH$ ) and a base ( $CH_3COO^-$ ). Therefore we can write the <u>henderson-hasselbach reaction</u>:

$pH~=~pKa+Log\frac{[CH_3COO^-]}{[CH_3COOH]}$

If we want to calculate the pH, we have to <u>calculate the pKa</u>:

$pH=-Log~Ka=4.76$

According to the problem, we have the <u>same concentration</u> for the acid and the base 0.1M. Therefore:

$[CH_3COO^-]=[CH_3COOH]$

If we divide:

$\frac{[CH_3COO^-]}{[CH_3COOH]}~=~1$

If we do the Log of 1:

$Log~1=~zero$

So:

$pH~=~pKa$

With this in mind, the pH is 4.76.

I hope it helps!

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3 years ago

Girl does not see a puddle of liquid on the lab table and accidentally touches the liquid. What should hiro do next?

Shalnov [3]

Tell the teacher they have touched an unidetified liquid. This is because "hiro" can have a reaction with the chemical he touched that can harm his health.

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3 years ago

Identify the parts of the telescope.

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Eyepiece, finder-scope, optical tube, aperture, focuser, and mount

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