3 years ago

Ca(s) + O2(g) - O A. Cao(s) B. Ca2O(s) O C. 2Ca(s) + O2(g) O D. CaO2(s)

1 answer:

Pepsi [2]3 years ago

5 0

Answer:

bbbbnnnnnnnnnnnnnnn

Explanation:

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suter [353]

According to my astronomy book, it's about 0.206

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3 years ago

AURORKA [14]

Answer: There are $3.011 \times 10^{23}$ atoms present in 0.500 mol of $CO_{2}$ .

Explanation:

According to the mole concept, there are $6.022 \times 10^{23}$ atoms present in 1 mole of a substance.

In a molecule of $CO_{2}$ there is only one carbon atom present. Therefore, number of carbon atoms present in 0.500 mol of $CO_{2}$ are as follows.

$1 \times 0.500 \times 6.022 \times 10^{23}\\= 3.011 \times 10^{23}$

Thus, we can conclude that there are $3.011 \times 10^{23}$ atoms present in 0.500 mol of $CO_{2}$ .

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alekssr [168]

Answer: Colombia

Explanation:

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3 years ago

Veseljchak [2.6K]

Answer:

C contains one N and three I atoms

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LUCKY_DIMON [66]

Answer: The products usually weigh more than the reactants.

Explanation:

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2 years ago