D have the same opinion on the contain resisting
If we let x be the number of sample which contains the atoms of carbon (C). Given that according to study, the amount of atoms in carbon sample that are C-13 atoms is 1.07%, the mathematical set-up that would represent the sample is,
= (0.0107)(C)
The balanced equation for the above reaction is as follows;
2Ca + O₂ ---> 2CaO
stoichiometry of Ca to O₂ is 2:1
we first need to find the limiting reactant
number of Ca moles - 6.84 mol
number of O₂ moles - 4.00 mol
if Ca is the limiting reactant
if 2 mol of Ca reacts with 1 mol of O₂
then 6.84 mol of Ca reacts with - 6.84 / 2 = 3.42 mol of O₂
this means that Ca is the limiting reactant and O₂ is in excess
therefore amount of CaO produced depends on amount of limiting reactant present
stoichiometry of Ca to CaO is 2:2
number of moles of Ca reacted = number of CaO moles formed
number of moles of CaO formed - 6.84 mol
answer is 6.84 mol
Answer:
the basic difference btw alkane and alkene is the presence of single and double bond respectively.first is saturated hydrocarbon while the latter is unsaturated
Hope this helps you buddy!!
