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KATRIN_1 [288]
3 years ago
11

PLSSS HELP MEECH3COOH + MgCH3-COOH+MgOCH3 -COOH + Mg(OH)2CH3-COOH + MgCO3​

Chemistry
1 answer:
iogann1982 [59]3 years ago
4 0

Explanation:

CH3COOH + Mg --> Mg(CH3COO)2 + H2

CH3COOH + MgO --> H2O + Mg(CH3COO)2

CH3COOH + Mg(OH)2 --> H2O + (CH3COO)2Mg

CH3COOH + MgCO3 --> (CH3COO)2Mg + CO2 + H2O.

<em>*</em><em>equations</em><em> </em><em>are </em><em>not </em><em>balanced.</em>

hope it helps. :)

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A high concentration of water has ____________ dissolved particles than a low water concentration.
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A high concentration of water has <u>fewer</u> dissolved particles than a low water concentration.

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2 years ago
Which describes the path of energy that a gas powered car uses to drive along a road?
harkovskaia [24]

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3 years ago
The heat of vaporization of a liquid is 84.0 J/g. How many joules of heat would it take to completely vaporize 172 g of this liq
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Answer:

14,448 J of heat would it take to completely vaporize 172 g of this liquid at its boiling point.

Explanation:

The heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to Q = m*L, where L is called the latent heat of the substance and depends on the type of phase change.

During the evaporation process, a substance goes from a liquid to a gaseous state and needs to absorb a certain amount of heat from its immediate surroundings, which results in its cooling. The heat absorbed is called the heat of vaporization.

So, it is called "heat of vaporization", the energy required to change 1 gram of substance from a liquid state to a gaseous state at the boiling point.

In this case, being:

  • Q=?
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and replacing in the expression Q = m*L you get:

Q=172 g*84 \frac{J}{g}

Q=14,448 J

<u><em>14,448 J of heat would it take to completely vaporize 172 g of this liquid at its boiling point.</em></u>

5 0
3 years ago
Match the symbol for each element with the name of the element. 1. hydrogen K 2. helium Mg 3. sodium He 4. magnesium H 5. potass
insens350 [35]

Answer:

1. hydrogen - H

2. helium - He

3. sodium - Na

4. magnesium - Mg

5. potassium - K

Explanation:

Hydrogen is the element of group 1 and first period. The atomic number of hydrogen is 1 and the symbol of the element is H.

The electronic configuration of the element hydrogen is:-

1s^1

Helium is the element of group 18 and first period. The atomic number of helium is 2 and the symbol of the element is He.

The electronic configuration of the element helium is:-

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The electronic configuration of the element sodium is:-

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Magnesium is the element of group 2 and third period. The atomic number of magnesium is 12 and the symbol of the element is Mg.

The electronic configuration of the element magnesium is:-

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Potassium is the element of group 1 and forth period. The atomic number of potassium is 19 and the symbol of the element is K.

The electronic configuration of the element potassium is:-

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5 0
3 years ago
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Cerrena [4.2K]

Answer: The concentration of H^{+} ions in vinegar is 0.001 M.

Explanation:

Given: pH = 3.0

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The expression for pH is as follows.

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Substitute the value into above expression as follows.

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Thus, we can conclude that the concentration of H^{+} ions in vinegar is 0.001 M.

5 0
3 years ago
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