Question

A bird flies at a speed of 15 m/s for 10 seconds, 1,200 m/min for 0.17 minute, and 2,500 cm/s for 5,000 milliseconds. What is the bird’s average speed?

Answer 1

15 m/s for 10 sec; distance covered = (15 x 10) = 150 m
Second segment:
20 m/s for 20 sec; distance covered = (20 x 20) = 400 m
Third segment:
30 m/s for 15 sec; distrance covered = (30 x 15) = 450 m
Total time = (10s + 20s + 15s) = 45 sec
Total distance = (150m + 400m + 450m) = 1,000 m (1 km)
Average speed = (1,000 m) / (45 sec) = 22.22 m/s ...

Answer 2

Answer:

Explanation:

average speed=distance travelled/time taken

distance=speed*time

15*10=150 m

1200 m/min=20 m/s

0.17 minute=10.2 seconds

20*10.2=204 m

2500 cm/s=25 m/s

5000 milliseconds=5 seconds

25*5=125 m

125+150+204=479 m

10.2+5+10=25.2

479/25.2=19.0