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3 years ago

Use the periodic table to determine the electron configuration for aluminum (AI) and arsenic (As) in

Chemistry

1 answer:

Harlamova29_29 [7]3 years ago

4 0

Answer:

Aluminum; [Ne]3s²3p¹

Arsenic; [Ar]3d¹⁰4s²4p³

Explanation:

<em>Aluminum</em>

From the periodic table, we have that aluminum, Al, is located in period 3, and group 3A of the periodic table

Therefore, the noble gas that comes before aluminum in the periodic table is neon Ne

The electronic configuration of aluminum is 1s²2s²2p⁶3s²3p¹

The electronic configuration of neon is 1s²2s²2p⁶

Therefore, the electronic configuration of aluminum in noble gas notation (Ne) is therefore;

[Ne]3s²3p¹

<em>Arsenic</em>

Arsenic is located after argon, Ar on the periodic table

The electronic configuration of arsenic is 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p³

The electronic configuration of argon is 1s²2s²2p⁶3s²3p⁶

The electronic configuration of arsenic in noble gas notation (Ar) is given as follows;

[Ar]3d¹⁰4s²4p³

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A chef is serving a lunch special with 1 sandwich and 2 corn cobs per plate. If there are 5 sandwiches and 14 corn cobs, what is

shtirl [24]

5 plates is the highest amount that can be served

There’s only 5 sandwiches so 7 is automatically ruled out, there’s 14 corn cobs and 5 sandwiches only need 10 so it works out

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3 years ago

Read 2 more answers

Is kp or kc larger (both at 300 k) for the reaction 2 nh3(g) ⇀↽ n2(g) + 3 h2(g) ? 1. they are both the same. 2. kc is larger. 3.

fgiga [73]

The equation is 2 NH3 (g) â‡€â†˝ N2 (g) + 3 H2 (g)
Difference in the number of moles delta n = ((3 + 1) - 2) = 4 - 2 = 2
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Kp / Kc = (R x T) ^2 Based on the temperature value (300 K), we can conclude that Kp is Larger.

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3 years ago

50.0 g of NaNO3 are dissolved into enough water to make 250 mL of solution. What is the molarity of this solution?

d1i1m1o1n [39]

Answer:

2.35 M

Explanation:

Molarity is mol/L of solution. We have to convert the g to mol and the mL to L. G to mol uses the molar mass of the compound. The molar mass of NaNO₃ is 85.00g/mol.

$50.0gNaNO3*\frac{1molNaNO3}{85.00gNaNO3} = 0.588molNaNO3$

Then you have to convert mL to L.

$250mL*\frac{1L}{1000mL} = 0.250L$

Now divide the mol by the L.

$\frac{0.588mol NaNO3}{0.250L} = 2.352 M$

Round to the smallest number of significant figures = 2.35M

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3 years ago

Cacl2+na3po4 ca3po42 + nacl

Alex787 [66]

<h3>Answer:</h3>

3CaCl₂ + 2Na₃PO₄→ Ca₃(PO₄)₂ + 6NaCl

<h3>Explanation:</h3>

We are given the Equation;

CaCl₂ + Na₃PO₄→ Ca₃(PO₄)₂ + NaCl

Assuming the question requires us to balance the equation;

A balanced chemical equation is one that has equal number of atoms of each element on both sides of the equation.
Balancing chemical equations ensures that they obey the law of conservation of mass in chemical equations.
According to the law of conservation of mass in chemical equation, the mass of the reactants should always be equal to the mass of the products.
Balancing chemical equations involves putting appropriate coefficients on the reactants and products.

In this case;