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1 year ago

What type of water molecules have the greater tendency to condense to the liquid state from the gaseous state

1 answer:

4 0

'The slower moving' type of water molecules have the greater tendency to condense to the liquid state from the gaseous state.

If the molecules speed up it means that energy has been added to the system. Eventually, therefore, the water would evaporate into steam (or water vapour) provided the energy was continued to be added to the system.

Vice versa if the molecules are slowed down then the water molecules in gas would condense and change their state from gas to liquid.

Condensation is the process where water vapour becomes liquid. It is the reverse of evaporation, where liquid water becomes a vapour.

Condensation happens one of two ways: Either the air is cooled to its dew point or it becomes so saturated with water vapour that it cannot hold any more water.

Learn more about condensation here : brainly.com/question/1268537

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Calculate the pH of a 0.0150 M HNO3 solution. Assume HNO3

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Answer: 1.824

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Based on the standard free energies of formation, which of the following reactions represent a feasible way to synthesize the pr

yuradex [85]

Explanation:

According the equation of Gibb's free energy -

∆G = ∆H -T∆S

∆G = is the change in gibb's free energy

∆H = is the change in enthalpy

T = temperature

∆S = is the change in entropy .

And , the sign of the ΔG , determines whether the reaction is Spontaneous or non Spontaneous or at equilibrium ,

i.e. ,

• ΔG < 0 , the reaction is Spontaneous

• ΔG > 0 , the reaction is non Spontaneous

• ΔG = 0 , the reaction is at equilibrium

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ΔG > 0 , the reaction is non Spontaneous , the reaction is not feasible in the forward direction

2Na(s) + O₂(g) → Na₂O₂ (s) ; ΔG⁰ f = − 447.7kJ/mol

ΔG < 0 , the reaction is Spontaneous , the reaction is feasible in the forward direction .

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ΔG > 0 , the reaction is non Spontaneous , the reaction is not feasible in the forward direction

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3 years ago

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3 years ago

Read 2 more answers

Kc for the reaction N2O4 <=> 2NO2 is 0.619 at 45 degrees C If 50.0g of N2O4 is introduced into an empty 2.10L container, w

Nadya [2.5K]

Answer:

p(N2O4) = 0.318 atm

p(NO2) = 7.17 atm

Explanation:

Step 1: Data given

Kc = 0.619

Temperature = 45.0 °C

Mass of N2O4 = 50.0 grams

Volume = 2.10 L

Molar mass N2O4 = 92.01 g/mol

Step 2: The balanced equation

N2O4 ⇔ 2NO2

Step 3: Calculate moles N2O4

Moles N2O4 = 50.0 grams / 92.01 g/mol

Moles N2O4 = 0.543 moles

Step 4: The initial concentration

[N2O4] = 0.543 moles/2.10 L = 0.259 M

[NO2]= 0 M

Step 5: Calculate concentration at the equilibrium

For 1 mol N2O4 we'll have 2 moles NO2

[N2O4] = (0.259 -x)M

[NO2]= 2x

Step 6: Calculate Kc

Kc = 0.619= [NO2]² / [N2O4]

0.619 = (2x)² / (0.259-x)

0.619 = 4x² / (0.259 -x)

x = 0.1373

Step 7: Calculate concentrations

[N2O4] = (0.259 -x)M = 0.1217 M

[NO2]= 2x = 0.2746 M

Step 8: The moles

Moles = molarity * volume

Moles N2O4 = 0.1217 M * 2.10 = 0.0256 moles

Moles NO2 = 0.2746 M * 2.10 = 0.577 moles

Step 9: Calculate partial pressure

p*V = n*R*T

⇒ with p = the partial pressure

⇒ with V = the volume = 2.10 L

⇒ with n = the number of moles

⇒ with R = the gas constant = 0.08206 L*atm/mol*K

⇒ with T = the temperature = 45 °C = 318 K

p = (nRT)/V

p(N2O4) = (0.0256 *0.08206 * 318)/ 2.10

p(N2O4) = 0.318 atm

p(NO2) = (0.577 *0.08206 * 318)/ 2.10

p(NO2) = 7.17 atm

6 0

3 years ago