so the answer for this particular question is unknown because I havent done this course before
Answer:
The rational zero of the polynomial are .
Step-by-step explanation:
Given polynomial as :
f(x) = 4 x³ - 8 x² - 19 x - 7
Now the ration zero can be find as
,
where P is the constant term
And Q is the coefficient of the highest polynomial
So, From given polynomial , P = -7 , Q = 4
Now ,
I.e =
Or, The rational zero are
Hence The rational zero of the polynomial are . Answer
= > x² + 7x + 12 = 12
= > x² + ( 4 + 3 )x + 12 = 12
= > x² + 4x + 3x + 12 = 12
= > x( x + 4 ) + 3( x + 4 ) = 12
= > ( x + 4 ) ( x + 3 ) = 12
Percy did correct till this step. But by doing like this, Percy can't get the values of the variable x.
Percy should follow the following steps :
= > x² + 7x + 12 = 12
Add -12 on both sides,
= > x² + 7x + 12 - 12 = 12 - 12
= > x² + 7x = 0
= > x( x + 7 ) = 0
= > ( x = 0 ) or ( x + 7 = 0 )
= > ( x = 0 ) or ( x = - 7 )
Hence, required value(s) of x is 0 or -7