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katovenus [111]
3 years ago
13

How are the raincoats waterproof? explain​

Physics
1 answer:
Reil [10]3 years ago
7 0

Answer:

Rain jackets are coated in durable water-repellant (DWR) finish, a hydrophobic glaze that allows the coats to be breathable, yet waterproof. It lets water vapor—like sweat—out, but keeps rain from getting in. ... Without a DWR, the raincoat is just a coat. So, you'll need to recoat it.

Explanation:

This is according to the web

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Conservation of Momentum<br> No one likes you little trolls please send an actual answer
Olin [163]

Hello!

This is an example of an inelastic collision, where the two objects "stick" to each other after their collision. (The Goalkeeper CATCHES the puck).

We can write out the conservation of momentum formula:

m1vi + m2vi = m1vf + m2vf

Let:

m1 = mass of puck

m2 = mass of the goalkeeper

We know that the initial velocity of the goalkeeper is 0, so:

m1vi + m2(0) = m1vf + m2vf

m1vi = m1vf + m2vf

The final velocities will be the same, so:

m1vi = (m1 + m2)vf

Plug in the given values:

(0.16)(40)/ (0.16 + 120) = vf ≈ 0.0533 m/s

Using the equation for momentum:

p = mv

The object with the LARGER mass will have the greater momentum. Thus, the Goalkeeper has the largest momentum as p = mv; a greater mass correlates to a greater momentum since the velocity is the same between the two objects. The puck would have a momentum of p = (.16)(0.0533) = 0.008528 kgm/s, whereas the goalkeeper would have a momentum of

p =  (120)(0.0533) = 6.396 kgm/s.

3 0
2 years ago
In the diagrams, the solid green line represents Earth's rotational axis and the dashed red line represents the magnetic field a
Elis [28]

Answer:

b

Explanation:

5 0
3 years ago
Read 2 more answers
A coil is connected in series with a 19.0 kΩ resistor. An ideal 50.0 V battery is applied across the two devices, and the curren
Gre4nikov [31]

Answer:

inductance of the coil 29.3767  H

Explanation:

given data

resistor R =  19.0 kΩ = 19 × 10³ Ω

potential applied V  = 50.0 V

current I = 2.20 mA  =  2.20 × 10^{-3} A

time t = 2.80 ms = 2.80 × 10^{-3} s

solution

we know for maximum current in circuit that is

current = V ÷ R   .........1

current =  \frac{50}{19\times 10^3}

current = 2.63 × 10^{-3} A

so at time t = 0

t = -\frac{L}{R} ln(1-\frac{I_f}{I_{max}})  

2.80 \times 10^{-3} = -\frac{L}{19\times 10^3} ln(1-\frac{2.20\times 10^{-3}}{2.63\times 10^{-3}}})  

L = 29.3767

3 0
3 years ago
Transverse waves travel with a speed of 20.0 m/s on a string under a tension of 6.00 N. What tension is required for a wave spee
marta [7]

Based on the sped of the waves and the tension as well as the needed wave speed, the required tension is 13.5 N.

<h3>What is the required tension?</h3>

Given the initial tension and speed, the tension that is required can be found by the formula:

= Initial tension x (Required speed / Initial speed)²

Solving gives:

= 6 x (30 / 20)²

= 6 x 9/4

= 13.5 N

In conclusion, the tension required is 13.5N.

Find out more on the tension on a wire at brainly.com/question/14290894.

#SPJ4

3 0
1 year ago
A child and her mother are at the park. The child walks around the rectangular park while her mom waits on a bench. The child re
kati45 [8]

the correct answer is 0

7 0
3 years ago
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