How are the raincoats waterproof? explain
1 answer:
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Answer:
T = 295.57 s
Explanation:
given,
mass of the rocket = 200 Kg
mass of the fuel = 100 Kg
acceleration = 35 m/s²
time, t = 35 s
time taken by the rocket to hit the ground, = ?
Final speed of the rocket when fuel is empty
using equation of motion
v = u + a t
v = 0 + 35 x 35
v = 1225 m/s
height of the rocket where fuel is empty
v² = u² + 2 a s
1225² = 0 + 2 x 35 x h₁
h₁ = 21437.5 m
After 35 s the rocket will be moving upward till the final velocity becomes zero.
Now, using equation of motion to find the height after 35 s
v² = u² + 2 g h₂
0² = 1225² + 2 x (-9.8) h₂
h₂ = 76562.5 m
total height = h₁ + h₂
= 76562.5 m + 21437.5 m = 98000 m
now, time taken by before the rocket hit the ground
using equation of motion
negative sign is used because the distance travel by the rocket is downward.
4.9 t² - 1225 t - 13500 = 0
t = 260.57 s
neglecting the negative sign
total time the rocket was in air
T = t₁ + t₂
T = 35 + 260.57
T = 295.57 s
Time for which rocket was in air is equal to 295.57 s.
Answer:
(a) 80.36 m/s^2
(b) 0.0933 second
Explanation:
initial velocity, u = 7.5 m/s
final velocity, v = 0 m/s
distance moved, s = 0.350 m
(a) Let a be the deceleration.
Use third equation of motion
a = 80.36 m/s^2
Thus, the deceleration is 80.36 m/s^2.
(b) Let the time taken is t
Use first equation of motion
v = u + a t
0 = 7.5 + 80.36 x t
t = 0.0933 second