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Valentin [98]
3 years ago
10

A current of 6.0 A runs through a circuit for 2.5 minutes.

Physics
2 answers:
Mekhanik [1.2K]3 years ago
5 0
Current is measured as charge per unit time. To get change, simply multiply the current with time:

6A*2.5mins = 6A*(2.5*60)seconds = 900Coulombs
Sunny_sXe [5.5K]3 years ago
3 0

Answer: 900 C

Explanation:

The intensity of current is defined as:

I=\frac{Q}{t}

where

Q is the amount of charge that passes through a given point in the circuit

t is the time taken

In this problem, we know the current in the circuit, I=6.0 A, and we know the time taken, which is

t=2.5 min \cdot 60 s/min = 150 s

Therefore we can re-arrange the equation above to calculate the charge delivered to the circuit:

Q=It=(6.0 A)(150 s)=900 C

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4. The atmosphere is composed of about 78% nitrogen, 21% oxygen, and 1% argon. Typical atmospheric pressure in Boulder, Colorado
photoshop1234 [79]

<u>ANS</u>

<u>Step</u> <u>1</u> :Explanation of required formula.

According to Dalton's Law of Partial Pressures, the partial pressure of a component of a gaseous mixture depends on the mole ratio of said component and the total pressure of the gaseous mixture

i.e Pi=Xi × Ptotal,

Here we don't know exactly how many moles of the mixture we have,

but we know that 78.0% of all the molecules present in the mixture are nitrogen molecules, 21.0% are oxygen molecules, and 1% are molecules of Ar gas.

As we know, a mole is simply a very large collection of molecules. In order to have one mole of a substance, we need to have 6.022 × 1023 molecules of that substance.

This means that the actual number of moles is not important here, because the ratio that exists between the number of molecules is equivalent to the ratio that exists between the number of moles.

Hence,

<u>Step</u> <u>2</u> : Calculate of mole fraction of the mixture.

mole fraction of nitrogen = 78 /100 = 0.78

mole fraction of O2 =

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mole fraction of Argon =

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<u>Step</u> <u>3</u> : Calculate the pressure contributed by each of the mixture.

The pressure contributed by N2 = mole fraction of N2 × Total pressure = 0.78 × 0.83 atm = 0.6474 atm

The pressure contributed by O2 = 0.21 × 0.83 atm = 0.1743 atm

The pressure contributed by N2 = 0.01 × 0.83 atm = 0.0083 atm.

<u>Tha</u><u>nk</u> <u>You</u> !!!!!!

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