Question

A current of 6.0 A runs through a circuit for 2.5 minutes.

Answer 1

Current is measured as charge per unit time. To get change, simply multiply the current with time:

$6A*2.5mins = 6A*(2.5*60)seconds = 900Coulombs$

Answer 2

Answer: 900 C

Explanation:

The intensity of current is defined as:

$I=\frac{Q}{t}$

where

Q is the amount of charge that passes through a given point in the circuit

t is the time taken

In this problem, we know the current in the circuit, I=6.0 A, and we know the time taken, which is

$t=2.5 min \cdot 60 s/min = 150 s$

Therefore we can re-arrange the equation above to calculate the charge delivered to the circuit:

$Q=It=(6.0 A)(150 s)=900 C$