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Klio2033 [76]
3 years ago
11

Why does a tadpole reabsorb its tail into its body?

Chemistry
2 answers:
vladimir1956 [14]3 years ago
4 0
The cells mutated is the answer
adelina 88 [10]3 years ago
3 0

Answer:

The cells mutated.

Explanation:

Lysosomes is the cell that digest the unwanted materials in the cytoplasm.

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25.0 mL of an HBr solution were titrated with 29.15 mL of a 0.205 M LiOH solution to reach the equivalence point. What is the mo
trapecia [35]

The molarity of HBr solution is 0.239 M

calculation

write the equation for reaction

that is LiOH +HBr → LiBr +H20

find the moles of LiOH used

moles =molarity x volume

=0.205 x 29.15 = 5.976 moles

by use of mole ratio between LiOH :HBr which is 1:1 the moles of HBr is therefore= 5.976 moles

Molarity of HCL= moles /volume

= 5.976/25 = 0.239 M

7 0
3 years ago
Where is most of an atom's atomic mass?
Kamila [148]

Answer:

The nucleus contains the majority of an atom's mass because protons and neutrons are much heavier than electrons, whereas electrons occupy almost all of an atom's volume. The diameter of an atom is on the order of 10−10 m, whereas the diameter of the nucleus is roughly 10−15 m—about 100,000 times smaller.

Explanation:

3 0
2 years ago
Read 2 more answers
A 10 mm Brinell hardness indenter is used for some hardness testing measurements of a steel alloy. a) Compute the HB of this mat
Lady_Fox [76]

Explanation:

(a)  The given data is as follows.  

         Load applied (P) = 1000 kg

         Indentation produced (d) = 2.50 mm

         BHI diameter (D) = 10 mm

Expression for Brinell Hardness is as follows.

                HB = \frac{2P}{\pi D [D - \sqrt{(D^{2} - d^{2})}]}    

Now, putting the given values into the above formula as follows.

                HB = \frac{2P}{\pi D [D - \sqrt{(D^{2} - d^{2})}]}                            = \frac{2 \times 1000 kg}{3.14 \times 10 mm [D - \sqrt{((10 mm)^{2} - (2.50)^{2})}]}  

                       = \frac{2000}{9.98}                          

                       = 200

Therefore, the Brinell HArdness is 200.

(b)     The given data is as follows.

               Brinell Hardness = 300

                Load (P) = 500 kg

               BHI diameter (D) = 10 mm

             Indentation produced (d) = ?

                      d = \sqrt{(D^{2} - [D - \frac{2P}{HB} \pi D]^{2})}

                         = \sqrt{(10 mm)^{2} - [10 mm - \frac{2 \times 500 kg}{300 \times 3.14 \times 10 mm}]^{2}}

                          = 4.46 mm

Hence, the diameter of an indentation to yield a hardness of 300 HB when a 500-kg load is used is 4.46 mm.

5 0
3 years ago
A sample of gas occupies 7.80 liters at 425=C2=B0C? What will be the volume= of the gas at 35=C2=B0C if the pressure does not ch
luda_lava [24]

To solve this we assume that the gas inside the balloon is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

T1 / V1 = T2 / V2

V2 = T2 x V1 / T1

V2 = 308.15 x 7.80 / 698.15

V2 =3.44 L


7 0
3 years ago
Is NaHCO3 a compound? Explain pls!
Slav-nsk [51]

Answer:

Yes it is

Explanation: because it is composed of identical molecules consisting of atoms of two or more chemical elements.

hope it helps <3

4 0
2 years ago
Read 2 more answers
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