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3 years ago

The reaction CH2CH2 + H2 → CH3CH3 is an example of

Chemistry

2 answers:

Tpy6a [65]3 years ago

7 0

Answer:

Addition reaction.

Explanation:

There are four possible type of reactions in an organic compound, generally.

a) substitution: where a group or atoms substitutes another group or atom. for example reaction of an alkyl halide with hydroxide ion to give alcohol, where hydroxide ion replaces a halide ion.

b) elimination: Where a group or atom get eliminated from a molecule. For example synthesis of an alkene from an alkyl halide by elimination of hydrogen and halogen.

c) rearrangement: Here there is no addition or substitution or elimination but the molecule undergoes some atomic rearrangements to give a stable form.

d) Addition : in this there is addition of a molecule on a double bond.

In the given example the alkene is undergoing addition reaction as hydrogen is being added on it to give saturated alkane molecule.

Viefleur [7K]3 years ago

4 0

The choices can be found elsewhere and as follows:

(1) substitution
(2) esterification
(3) addition
(4) fermentation

I believe the correct answer is option 3. The reaction CH2CH2 + H2 → CH3CH3 is an example of an addition reaction. It is a reaction where two or more molecules combine to form a larger one. Hope this answers the question.

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calcium and strontium are close to one another on thw oeriodic table. what do you know about their ionization energies ,their el

Firdavs [7]

Both Ca and Sr are in Group 2 of the Periodic Table, with Sr below Ca (see image)..

Ionization energies

They are both metals, so they have relatively low ionization energies.

Sr is below Ca in the Group, so Sr has the lower ionization energy.

Electron configurations

Their electron configurations both end in ns².

For example, the electron configuration of Ca is [Kr]4s² and that of Sr is [Kr]5s².

Physical chsrscteristics:

metallic lustre
malleable
ductile
good conductors of heat and electricity

Chemical characteristics

Both metals react with

• Hydrogen to form hydrides: M + H₂ ⟶ MH₂

• Oxygen to form oxides: 2M + O₂ ⟶ 2MO

• Nitrogen to form nitrides: 3M + N₂ ⟶ M₃N₂

• Halogens to form halides: M + X₂ ⟶ MX₂

• Water to displace hydrogen: M + 2H₂O ⟶ M(OH)₂ + H₂

4 0

3 years ago

Caffeine (C8H10N4O2) is a weak base with a pKb of 10.4. Calculate the pH of a solution containing a caffeine concentration of 41

RSB [31]

Answer:

pH → 7.47

Explanation:

Caffeine is a sort of amine, which is a weak base. Then, this pH should be higher than 7.

Caffeine + H₂O ⇄ Caffeine⁺ + OH⁻ Kb

1 mol of caffeine in water can give hydroxides and protonated caffeine.

We convert the concentration from mg/L to M

415 mg = 0.415 g

0.415 g / 194.19 g/mol = 2.14×10⁻³ mol

[Caffeine] = 2.14×10⁻³ M

Let's calculate pH. As we don't have Kb, we can obtain it from pKb.

- log Kb = pKb → 10^-pKb = Kb

10⁻¹⁰'⁴ = 3.98×10⁻¹¹

We go to equilibrium:

Caffeine + H₂O ⇄ Caffeine⁺ + OH⁻ Kb

Initially we have 2.14×10⁻³ moles of caffeine, so, after the equilibrium we may have (2.14×10⁻³ - x)

X will be the amount of protonated caffeine and OH⁻

Caffeine + H₂O ⇄ Caffeine⁺ + OH⁻ Kb

(2.14×10⁻³ - x) x x

We make the expression for Kb:

3.98×10⁻¹¹ = x² / (2.14×10⁻³ - x)

We can missed the -x in denominator, because Kb it's a very small value.

So: 3.98×10⁻¹¹ = x² / 2.14×10⁻³

√(3.98×10⁻¹¹ . 2.14×10⁻³) = x → 2.92×10⁻⁷

That's the [OH⁻]. - log [OH⁻] = pOH

- log 2.92×10⁻⁷ = 6.53 → pOH

14 - pOH = pH → 14 - 6.53 = 7.47

4 0

2 years ago

How do plants release energy

ololo11 [35]

Answer:

no but oxygen

Explanation:

no but oxygen

7 0

2 years ago

Read 2 more answers

1. The reaction below describes cellular respiration. Which compounds are the reactants and which are the

swat32

Answer:

C₆H₁₂O₆ and O₂ are reactant.

CO₂ and H₂O are products.

C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + ATP

Explanation:

There are two types of respiration:

1. Aerobic respiration

2. Anaerobic respiration

Aerobic respiration

It is the breakdown of glucose molecule in the presence of oxygen to yield large amount of energy. Water and carbon dioxide are also produced as a byproduct.

Glucose + oxygen → carbon dioxide + water + 38ATP

Anaerobic Respiration

It is the breakdown of glucose molecule in the absence of oxygen and produce small amount of energy. Alcohol or lactic acid and carbon dioxide are also produced as byproducts.

Glucose→ lactic acid/alcohol + 2ATP + carbon dioxide

This process use respiratory electron transport chain as electron acceptor instead of oxygen. It is mostly occur in prokaryotes. Its main advantage is that it produce energy (ATP) very quickly as compared to aerobic respiration.

Steps involve in anaerobic respiration are:

Glycolysis

Glycolysis is the first step of both aerobic and anaerobic respiration. It involve the breakdown of one glucose molecule into pyruvate and 2ATP.

Fermentation

The second step of anaerobic respiration is fermentation. It involve the fermentation of pyruvate into lactic acid or alcohol depending upon the organism in which it is taking place. There is no ATP produced, however carbon dioxide is released in this step.

8 0

3 years ago

What is the radius of a hydrogen atom whose electron is bound by 0.544 ev? express your answer with the appropriate units?

insens350 [35]

First, we need to calculate the principal quantum number n for this electron, using the equation:
E = (-13.60 eV) / (n x n)
where E is the energy that is used to bound the electron (here, E = - 0.544 eV).
- 0.544 eV = (-13.60 eV) / (n x n)
n x n = (- 13.60 eV) / (- 0.544 eV)
n x n = 25
n = 5

The orbital radius that is equal to the radius of a hydrogen atom is calculated using the equation:
r = 0.053 nm x n x n
r = 0.053 nm x 5 x 5
r = 0.053 nm x 25
r = 1.325 nm

6 0

2 years ago