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3 years ago

Weathering and erosion are the same thing. true or false? i personally think its false but just to be sure lol

2 answers:

8 0

False

weathering is the breaking of rocks into smaller and smaller pieces called sediments

erosion is the movement of these sediments by wind , water , gravity & ice to a new location

Charra [1.4K]3 years ago

5 0

Answer:

<em>It is false.</em>

Explanation:

<em>Weathering is the general process by which rocks are broken down at Earth's surface. Erosion is a set of processes that loosen and move soil and rock downhill or downwind. Umm...for example, imagine you are having ice cream in your hand out on a sunny day, if the ice-cream melts and falls down, it is called erosion and if the ice-cream melts but it doesn't fall down, it called weathering. </em>

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You have a 5-liter container with 1.30 x 1024 molecules of ammonia gas (NH3) at STP.

bogdanovich [222]

Answer:

3). 1.30 × 10^(24) molecules

Explanation:

From avogadro's law which state that equal volume of all gases at the same temperature and pressure contain the same number of molecules.

We can relate it to this question as;

V₁/n₁ = V₂/n₂

Where;

V₁ is initial volume

n₁ is initial number of molecules

V₂ is final volume

n₂ is final number of molecules

Thus at STP, we have V₁ = V₂ and as such Plugging in the relevant values gives;

5/(1.30 x 10^(24)) = 5/n₂

n₂ = 1.30 x 10^(24) molecules

6 0

3 years ago

Name the element which has twice the number of electrons in its second shell as in the first shell write it's electronic configu

Basile [38]

CARBON! :) it’s the 6th element

3 0

3 years ago

1.Bubbling or fizzing is an indicator of

hodyreva [135]

D is the answer since it is changing the element.

6 0

3 years ago

In which row has Aaron made an error in his chart?

hammer [34]

Answer:Row 2

Explanation:

7 0

4 years ago

Two unknown molecular compounds were being studied. A solution containing 5.00 g of compound A in 100. g of water froze at a low

Shtirlitz [24]

Answer:

Compound B.

Explanation:

The freezing point depression is a colligative property. It depends on the number of particles (moles) present in the solution.

$\Delta T_{\text{f}} = K_{\text{f}} b$

where b is the molal concentration

$b = \dfrac{\text{moles of solute}}{\text{kilograms of solvent}}\\\\n = \dfrac{\text{mass}}{\text{molar mass}} = \dfrac{m}{M}$

If m is constant (5 g), then

$n \propto \dfrac{1}{M}$

The compound with the greater molar mass has fewer moles and therefore fewer particles to depress the freezing point.

That must be Compound B, because Compound A has the lower freezing point.

7 0

3 years ago