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Slav-nsk [51]
3 years ago
5

Why are force fields used to describe magnetic force? A. Magnetic force acts between two objects that are not touching. B. Magne

tic force is a form of gravity. C. Magnetic force acts between any two objects with mass. D. Magnetic force can only attract objects.tic force?
Physics
1 answer:
bonufazy [111]3 years ago
5 0

Answer:

The Answer is D. Magnetic force can only attract objects.

Explanation:

Magnetic forces can cause attraction or repulsion depending on the effect caused by the movement of particles.

<h2><em><u>Edit: Pleas correct me if i'm wrong!!!!</u></em></h2>
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How many minutes in 1 hour
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Every 60 minutes is an hour

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If the center of mass passes outside the area of support of an object, what will happen to it?
defon

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If a vertical line extending down from an object's CG extends outside its area of support, the object will topple

Explanation:

We can understand better this situation using a diagram with the forces acting on it.

In the attached image we can see that when the gravity center is bouncing outside from the area of the pedestal, the object will be out of balance and will fall.

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3 years ago
Which of the following is the best definition of energy?
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Energy is the capacity to do some type of work
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20. Using the picture, how many neutrons does lithium have?
Igoryamba

Answer:

No. of Neutrons = 3

Explanation:

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Mass Number = No. of Protons + No. of Neutrons = 6

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Therefore,

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8 0
3 years ago
A 5.50-kg object is hung from the bottom end of a vertical spring fastened to an overhead beam. The object is set into vertical
iris [78.8K]

Answer:

17.71N/m

Explanation:

The period of the spring is expressed according to the expression;

T = 2 \pi \sqrt{\frac{m}{k} } \\

m is the mass of the object

k is the force constant

Given

m = 5.50kg

T = 3.50s

Substitute into the formula;

T = 2 \pi \sqrt{\frac{m}{k} } \\3.5 = 2 (3.14) \sqrt{\frac{5.5}{k} } \\3.5 = 6.28 \sqrt{\frac{5.5}{k} } \\\frac{3.5}{6.28} =  \sqrt{\frac{5.5}{k} } \\0.557 = \sqrt{\frac{5.5}{k} } \\square \ both \ sides\\0.557^2 = (\sqrt{\frac{5.5}{k} })^2 \\0.3106 = \frac{5,5}{k}\\k = \frac{5.5}{0.3106}\\k =  17.71N/m

Hence the force constant of the spring is 17.71N/m

4 0
3 years ago
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