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4 years ago

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Why are force fields used to describe magnetic force? A. Magnetic force acts between two objects that are not touching. B. Magne

tic force is a form of gravity. C. Magnetic force acts between any two objects with mass. D. Magnetic force can only attract objects.tic force?

1 answer:

bonufazy [111]4 years ago

5 0

Answer:

The Answer is D. Magnetic force can only attract objects.

Explanation:

Magnetic forces can cause attraction or repulsion depending on the effect caused by the movement of particles.

<h2><em><u>Edit: Pleas correct me if i'm wrong!!!!</u></em></h2>

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Two guy's masses have gained a velocity (not equal to zero) which means their momentum is now _____ .

olya-2409 [2.1K]

Yes The Velocity will change

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4 years ago

Read 2 more answers

in general, what happens to the energy, order, and spacing of particles when a solid turns to a liquid?

vodka [1.7K]

For a solid to change its state of matter into liquid, energy is applied or heat is being used. With a solid, particles are very compacted and still, with a liquid they are not as compacted but can still take a defined shape.

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3 years ago

Suppose our experimenter repeats his experiment on a planet more massive than Earth, where the acceleration due to gravity is g

Ne4ueva [31]

Answer:

C

Explanation:

- Let acceleration due to gravity @ massive planet be a = 30 m/s^2

- Let acceleration due to gravity @ earth be g = 30 m/s^2

Solution:

- The average time taken for the ball to cover a distance h from chin to ground with acceleration a on massive planet is:

t = v / a

t = v / 30

- The average time taken for the ball to cover a distance h from chin to ground with acceleration g on earth is:

t = v / g

t = v / 9.81

- Hence, we can see the average time taken by the ball on massive planet is less than that on earth to reach back to its initial position. Hence, option C

7 0

3 years ago

1. There is a famous intersection in Kuala Lumpur, Malaysia, where thousands of vehicles pass each hour. A 750 kg Tesla Model S

tigry1 [53]

Solution :

Let the positive $x-axis$ is along the East and the positive $y$ direction is along the north.

Given :

Mass of the Tesla car, $m_1$ = $750 \ kg$

Mass of the Ford car, $m_2 = 1250 \ kg$

Now let the initial velocity of Tesla car in the south direction be = $-v_1j$

The initial momentum of Tesla car, $p_1 = -750 \ v_1$

Let the initial velocity of Ford car in the east direction be = $v_2 \ i$

So the initial momentum of the Ford car is $p_2=1250\ v_2 \ i$

Therefore, the initial velocity of both the cars is $p_i = p_1+p_2$

$=1250 \ v_2 \ i - 750\ v_1 \ j$

Now the final velocity of both the cars is $v = 18 \ m/s$

So the vector form is :

$v = 18\cos 32\ i-18 \sin 32 \ j$

$= 15.26 \ i - 9.54 \ j$

Therefore the momentum after the accident is

$p_f=(m_1+m_2) \times v$

$=(750+1250) \times (15.26 \ i - 9.54 \ j)$

$= 30520\ i -19080\ j$

According to the law of conservation of momentum, we know

$p_i = p_f$

$1250 \ v_2 \ i - 750\ v_1 \ j$ $= 30520\ i -19080\ j$

$1250 \ v_2 = 30520$

$v_2=24.4 \ m/s$

From, $750\ v_1 = 19080$

We get, $v_1=25.4 \ m/s$

Therefore the speed of Tesla car before collision = 25.4 m/s

The speed of ford car before collision = 24.4 m/s

6 0

3 years ago

An electron is initially moving at 1.4 x 107 m/s. It moves 3.5 m in the direction of a uniform electric field of magnitude 120 N

algol13

Answer:

K.E = 15.57 x 10⁻¹⁷ J

Explanation:

First, we find the acceleration of the electron by using the formula of electric field:

E = F/q

F = Eq

but, from Newton's 2nd Law:

F = ma

Comparing both equations, we get:

ma = Eq

a = Eq/m

where,

E = electric field intensity = 120 N/C

q = charge of electron = 1.6 x 10⁻¹⁹ C

m = Mass of electron = 9.1 x 10⁻³¹ kg

Therefore,

a = (120 N/C)(1.6 x 10⁻¹⁹ C)/(9.1 x 10⁻³¹ kg)

a = 2.11 x 10¹³ m/s²

Now, we need to find the final velocity of the electron. Using 3rd equation of motion:

2as = Vf² - Vi²

where,

Vf = Final Velocity = ?

Vi = Initial Velocity = 1.4 x 10⁷ m/s

s = distance = 3.5 m

Therefore,

(2)(2.11 x 10¹³ m/s²)(3.5 m) = Vf² - (1.4 x 10⁷)²

Vf = √(1.477 x 10¹⁴ m²/s² + 1.96 x 10¹⁴ m²/s²)

Vf = 1.85 x 10⁷ m/s

Now, we find the kinetic energy of electron at the end of the motion:

K.E = (0.5)(m)(Vf)²

K.E = (0.5)(9.1 x 10⁻³¹ kg)(1.85 x 10⁷ m/s)²

<u>K.E = 15.57 x 10⁻¹⁷ J</u>

4 0

3 years ago