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Tamiku [17]
3 years ago
6

A shopping cart rolls from x=19.9m to x=5.40m with an average velocity of -0.418m/s. How much time did it take? (unit=s)

Physics
1 answer:
andrew11 [14]3 years ago
8 0

Given

initial position = Xi= 19.9m

Final position Xf = 5.4m

Average velocity= Va = -0.418m/s

it shows displacement is reverse.

To find  t=?

As   Va = (Xf- Xi) / t

t = (Xf-Xi) / ( Va)

t = ( 5.4-19.9) / (-0.418)

t = (-14.5 ) / (-0.418)   (-ve sign cancel out at numerator and denominator)

t =34.69 s

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A bungee cord can stretch, but it is never compressed. When the distance between the two ends of the cord is less than its unstr
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Answer:

Explanation:

Given that

g=9.8m/s²

The spring constant is

k=50N/m

The length of the bungee cord is

Lo=32m

Height of bridge which one end of the bungee is tied is 91m

A steel ball of mass 92kg is attached to the other end of the bungee.

The potential energy(Us) of the steel ball before dropped from the bridge is given as

P.E= mgh

P.E= 92×9.8×91

P.E= 82045.6 J

Us= 82045.6 J

Potential energy)(Uc) of the cord is given as

Uc= ½ke²

Where 'e' is the extension

Then the extension is final height extended by cord minus height of cord

e=hf - hi

e=hf - 32

Uc= ½×50×(hf-32)²

Uc=25(hf-32)²

Using conservation of energy,

Then,

The potential energy of free fall equals the potential energy in string

Uc=Us

25(hf-32)²=82045.6

(hf-32)² = 82045.6/25

(hf-32)²=3281.825

Take square root of both sides

√(hf-32)²=√(3281.825)

hf-32=57.29

hf=57.29+32

hf=89.29m

We neglect the negative sign of the root because the string cannot compressed

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3 years ago
What is the Net Force?
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2 years ago
In major league baseball, the pitcher's mound is 60 feet from the batter. If a pitcher throws a 85 mph fastball, how much time e
Nostrana [21]
The given from your problem are the following:
V = 85mph (This is miles per hour)
d = 60 feet

If you notice the units do not match. Before we can do anything else, we need to make the figures match. 

In this case, we will convert 85miles per hour to feet per hour.  There are 5,280 feet in 1 mile. 
\frac{85miles }{hr} x \frac{5,280feet}{1miles} = \frac{448,800feet}{hr}

But wait! If you think about the scenario, you are looking for how long it will take for the ball to reach the bat. The most applicable unit of time to use here is second. It would be very hard to really measure a short and instantaneous event in hours. So we convert it into feet per second: 

There are 3,600 seconds in 1 hour.

\frac{448,800feet }{hour} x \frac{1hour}{3,600seconds} = \frac{448,800feet}{3,600 seconds} = 124.67ft/s

So now we have our new given as:

v = 124.67ft/s
d = 60 ft

The formula for time can be derived from the formula from velocity, which is:
velocity = \frac{distance}{time}

The formula of time will then be:
time= \frac{distance}{velocity}

All you need to do is plug in what you know and solve for what you don't know. 

time= \frac{60feet}{124.67ft/s}

time= 0.48s

The answer then is 0.48s.

If you want this in hours, just divide the value in seconds by 3,600. The answer would then be 0.00013hr. (See how small it is? This is why seconds would be a more appropriate measure.)
8 0
3 years ago
Pls help! True or False?
jasenka [17]

Answer:

True

Explanation:

i hope it helps

please follow me

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2 years ago
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