2p+3c=24
p+c=10
solve for p: p= 10-c
Substitute for p: 20-2c+3c=24
add the Cs: 20+c=24
Subtract: c=4
So four people ordered a chicken sandwich.
Answer:
Simplifying
(2j + 1) * 9 + -7j = 0
Reorder the terms:
(1 + 2j) * 9 + -7j = 0
Reorder the terms for easier multiplication:
9(1 + 2j) + -7j = 0
(1 * 9 + 2j * 9) + -7j = 0
(9 + 18j) + -7j = 0
Combine like terms: 18j + -7j = 11j
9 + 11j = 0
Solving
9 + 11j = 0
Solving for variable 'j'.
Move all terms containing j to the left, all other terms to the right.
Add '-9' to each side of the equation.
9 + -9 + 11j = 0 + -9
Combine like terms: 9 + -9 = 0
0 + 11j = 0 + -9
11j = 0 + -9
Combine like terms: 0 + -9 = -9
11j = -9
Divide each side by '11'.
j = -0.8181818182
Simplifying
j = -0.8181818182
Answer: a) yNA/100
b) NA(y-x)/100
c) (NA)/B
Step-by-step explanation:
a) The total amount of dollars owned by the shares' owner = N number of shares × A dollars per share = NA dollars
This total is then transferred to buy B shares which then appreciates by y%.
The amount of increase in portfolio from January to June = y% of total dollars invested = y% of NA dollars = yNA/100
b) If the shares were left with A, the increase in portfolio from January to June would be x% and = x% of the total Dollar amount = x% of NA dollars = xNA/100
How much more money made in that time would be the difference in interest, between taking the dollars to invest in share B or keeping the dollars on investment A
That is, (yNA/100) - (xNA/100) = NA(y-x)/100
c) Total dollars available after sale of the A stock = NA
Number of B stock this dollar can buy = Total dollars available/amount of B stock per share
That is, (NA)/B
QED!
Answer:
The expected value of the winnings for a single-ticket purchase is -$1.0016.
Step-by-step explanation:
The total number of tickets sold is, <em>N</em> = 1250.
Cost of one ticket is, $4.
Let <em>X</em> = amount of prize.
The prize distribution is as follows:
1 Grand price = $3000
1 Second prize = $450
10 Third prize = $25
The expected value <em>X</em> can be computed using the formula:
Compute the probability distribution of <em>X</em> as follows:
Prize Amount (X) P (X) x · P (X)
1 Grand prize $3000 
1 Second prize $450 
10 Third prize $25 
No prize -$4 
TOTAL 1.0000 -1.0016
Thus, the expected value of the winnings for a single-ticket purchase is -$1.0016.
The answer is (-1,7)
I got this answer because to solve a system, you find the point on the graph where both lines intersect. And that point in this graph is (-1,7). Hope this helps!:)))))
