Answer:
<u>The Eastbound train speed is 76.5 miles per hour and the Westbound train speed is 79.5 miles per hour.</u>
Step-by-step explanation:
1. Let's review all the information provided for solving this question:
Eastbound train speed = x
Westbound train speed = x + 3 miles per hour (The speed of the westbound train is 3mph greater than the speed of the eastbound train)
Duration of trip = 3 hours
Distance between trains after 3 hours = 468 miles
2. Let's find the speed of each train, using the following equation:
3x + 3(x + 3) = 468
3x + 3x + 9 = 468
6x + 9 = 468
6x = 468 - 9 (Subtracting 9 at both sides)
6x = 459
x = 459/6 (Dividing by 6 at both sides)
x = 76.5 miles per hour
<u>The Eastbound train speed is 76.5 miles per hour and the Westbound train speed is 79.5 miles per hour.</u>
3. Proof that x = 76.5 is correct
3x + 3(x + 3) = 468
3 (76.5) + 3 (76.5 + 3) = 468
229.5 + 238.5 = 468
<u>468 = 468</u>
<u>The value of x = 76. 5 is correct. And now we know that the Eastbound train has traveled 229.5 miles since the departure from Cleveland and the Westbound train 238.5 miles.</u>
Answer:
1, 2, 3, 6, 9, 18, 27, 54
Step-by-step explanation:
1x54=54
2x27= 54
3x18=54
4x9=54
just put all the factors in numerical order.
Answer:x= - 23/54
x= 3/20
Step-by-step explanation:
i hope this helps
Twice a number increased by 5= 2x+5
5 decreased by twice a number= 5-2x
twice the difference of a number and 5= 2(x-5)
Twice the sum of a number and 5= 2(x+5)
Five subtracted from twice a number= 2x-5
Twice a number, less 5= 2x-5
Answer:
........
Step-by-step explanation:
you didnt give a proper question so i answed with ........
