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Molodets [167]
2 years ago
15

MgCl2 + AgNO3 → AgCl + Mg(NO3)2

Chemistry
2 answers:
Law Incorporation [45]2 years ago
6 0

Answer:

MgCl2 + 2AgNO3 → 2AgCl + Mg(NO3)2

Explanation:

I'm assuming you want to balance it so...

The first thing I see is that there are two chlorines on the reactant side and one on the product side

Adding a coefficient of 2 would get 2AgCl2

Now there are two silvers on the reactant side, so add a 2 to AgNO3 on the products side. Now they are all balanced.

If that is not what you are looking for let me know!

rodikova [14]2 years ago
3 0

Answer:

The answer is: MgCl2 + 2AgNO3 → 2AgCl + Mg(NO3)2

So basically put; blank, 2, 2, blank

Hope this helps :)) <3

Explanation:

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When the alkanes below are chlorinated they produce 3 monochloro substitution products. These isomers have the same chemical formula, but their atoms arrangements are different.

What are constitutional versus isomeric isomers?

Although structural (constitutional) isomers share the same chemical formula but their atoms are bonded in a different way. Stereoisomers have the same atomic configurations and chemical formulae. The groups' spatial orientation is the only thing which distinguishes the molecules distinguishes them from one another.

What are instances of stereoisomers?

According to the general definition of stereoisomers, stereoisomers are isomers with the same composition (i.e., the same parts), but different orientations in space. Stereoisomers are of two different types which are enantiomers and diastereomers.

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1 year ago
How many moles of ammonium ions are in 125 mL of 1.40 M NH4NO3 solution? ________ moles (give answer with correct sig figs in un
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The number of mole of ammonium ion, NH₄⁺ in the solution is 0.175 mole

We'll begin by calculating the number of mole of NH₄NO₃ in the solution. This can be obtained as follow:

Volume = 125 mL = 125 / 1000 = 0.125 L

Molarity = 1.40 M

<h3>Mole of NH₄NO₃ =? </h3>

Mole = Molarity x Volume

Mole of NH₄NO₃ = 1.40 × 0.125

<h3>Mole of NH₄NO₃ = 0.175 mole</h3>

Finally, we shall determine the number of mole of ammonium ion, NH₄⁺ in the solution. This can be obtained as follow:

NH₄NO₃(aq) —> NH₄⁺(aq) + NO₃¯(aq)

From the balanced equation above,

1 mole of NH₄NO₃ contains 1 mole of NH₄⁺

Therefore,

0.175 mole of NH₄NO₃ will also contain 0.175 mole of NH₄⁺

Thus, the number of mole of ammonium ion, NH₄⁺ in the solution is 0.175 mole

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