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mixer [17]
3 years ago
6

. What is the density of a block of plastic if the volume of the block is 5 cm and the mass is 17.2 g?

Chemistry
1 answer:
stellarik [79]3 years ago
5 0

Answer:

<h3>The answer is 3.44 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 17.2 g

volume = 5 cm³

We have

density =  \frac{17.2}{5}  \\

We have the final answer as

<h3>3.44 g/cm³</h3>

Hope this helps you

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P4+ __02_ P4010 <br> I need help ASAP
klasskru [66]

Answer:

P_4+5O_2\rightarrow P_4O_{10}

Explanation:

Hello!

In this case, when we want to balance chemical reactions such as in this case, the idea is to equal to number of atoms of each element at each side of the equation according to the lay of conservation of mass, just as shown below:

P_4+5O_2\rightarrow P_4O_{10}

Because we have four phosphorous and ten oxygen atoms at each side.

Best regards!

8 0
3 years ago
Plants such as _______________ provided much nitrogen to the soil.
Allushta [10]

Answer:

Abiotic

Explanation:

Its because it includes water, sunlight, tempature and soil

6 0
2 years ago
Need help on atoms and molecules​
balu736 [363]

1-b

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3-a

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7 0
3 years ago
A 1.00 g sample of octane (C8H18) is burned in a bomb calorimeter with a heat capacity of 837J∘C that holds 1200. g of water at
lubasha [3.4K]

Answer:

The heat of combustion for 1.00 mol of octane is  -5485.7 kJ/mol

Explanation:

<u>Step 1:</u> Data given

Mass of octane = 1.00 grams

Heat capacity of calorimeter = 837 J/°C

Mass of water = 1200 grams

Temperature of water = 25.0°C

Final temperature : 33.2 °C

<u> Step 2:</u> Calculate heat absorbed by the calorimeter

q = c*ΔT

⇒ with c = the heat capacity of the calorimeter = 837 J/°C

⇒ with ΔT = The change of temperature = T2 - T1 = 33.2 - 25.0 : 8.2 °C

q = 837 * 8.2 = 6863.4 J

<u>Step 3:</u> Calculate heat absorbed by the water

q = m*c*ΔT

⇒ m = the mass of the water = 1200 grams

⇒ c = the specific heat of water = 4.184 J/g°C

⇒ ΔT = The change in temperature = T2 - T1 = 33.2 - 25  = 8.2 °C

q = 1200 * 4.184 * 8.2 =  41170.56 J

<u>Step 4</u>: Calculate the total heat

qcalorimeter + qwater = 6863.4 + 41170. 56 = 48033.96 J  = 48 kJ

Since this is an exothermic reaction, there is heat released. q is positive but ΔH is negative.

<u>Step 5</u>: Calculate moles of octane

Moles octane = 1.00 gram / 114.23 g/mol

Moles octane = 0.00875 moles

<u>Step 6:</u> Calculate heat combustion for 1.00 mol of octane

ΔH = -48 kJ / 0.00875 moles

ΔH = -5485.7 kJ/mol

The heat of combustion for 1.00 mol of octane is  -5485.7 kJ/mol

8 0
3 years ago
90) Garrett has just purchased a beer distributorship. He wants to increase the Visibility of his firm inlocal markets, but he k
Otrada [13]

Answer: option C) gather information and identify stakeholders

Explanation:

The sales, distribution and advertisement of alcoholic beverages requires information on consumer protection, health risks, and environmental factors. And Garrett would simply get such from the relevant stakeholders like regulatory agencies.

Thus, Garrett should first gather information and identify stakeholders

3 0
3 years ago
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