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mixer [17]
3 years ago
6

. What is the density of a block of plastic if the volume of the block is 5 cm and the mass is 17.2 g?

Chemistry
1 answer:
stellarik [79]3 years ago
5 0

Answer:

<h3>The answer is 3.44 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 17.2 g

volume = 5 cm³

We have

density =  \frac{17.2}{5}  \\

We have the final answer as

<h3>3.44 g/cm³</h3>

Hope this helps you

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Diego has been observing how well a type of plant grows in diffrent locations.he convludes that location with bright sunlight is
andrew-mc [135]
Actually this is wrong because not all plants need sunlight to grow best in different locations because  take a cactus for example it can grow directly in your home and it doesn't need a lot of water or sunlight

4 0
3 years ago
A solution is 12.5% Na3PO, by mass. How many grams of Na3PO4
Harman [31]
<h2>Answer:  4.94 g   </h2>

Explanation:

Mass of solution of Na₃PO₄ = volume  × density

                                              =   35.9 mL × 1.10 g/mL

                                              =   39.49 g

Now, since the solution only contains 12.5% Na₃PO₄, then the mass of Na₃PO₄ is 12.5% of 39.49 g

                                 12.5% × 39.49 g = <u>4.94 g   </u>        

7 0
2 years ago
A flask contains 0.280 mol of liquid bromine, br2. Determine the number of bromine molecules present in the flask.
Nat2105 [25]

Answer:

              1.68 × 10²³ Molecules

Explanation:

                     As we know that 1 mole of any substance contains exactly 6.022 × 10²³ particles which is also called as Avogadro's Number. So in order to calculate the number of particles (molecules) contained by 0.280 moles of Br₂, we will use following relation,

           Moles  =  Number of Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹

Solving for Number of Molecules,

           Number of Molecules  =  Moles × 6.022 × 10²³ Molecules.mol⁻¹

Putting values,

           Number of Molecules  =  0.280 mol × 6.022 × 10²³ Molecules.mol⁻¹

           Number of Molecules  = 1.68 × 10²³ Molecules

Hence,

           There are 1.68 × 10²³ Molecules present in 0.280 moles of Br₂.

4 0
3 years ago
Problem page a virus has a mass of ×9.010−12mg and an oil tanker has a mass of ×3.0107kg . use this information to answer the qu
faltersainse [42]
A. The mass of one mole of the virus is calculated by multiplying the mass of a single virus by the Avogadro's number which is equal to 6.022 x 10^23. Performing this operation,

   mass = (9.0 x 10^-12 mg)(6.022 x 10^23) = 5.42 x 10^12 mg

In correct number of significant figures, the answer would only have to be 5.4 x 10^12 mg. 

b. The number of moles of the virus that will have the same mass as the oil tanker is calculated by dividing the mass of the oil tanker by the mass of one mole of the virus. Note that doing division, both would have to have the same units. 

       n = (3.0 x 10^7 kg) / (5.4 x 10^12 mg)(1 g/1000 mg)(1 kg/1000 g)

Simplifying,
               n = 6

In correct number of significant figures, the answer is 6.0. 
4 0
3 years ago
Read 2 more answers
1 loop in the primary coil and 8 loops in the secondary. If the secondary voltage is 120 V, what must be the primary voltage
Jet001 [13]

Answer:

V_{p} = 15 V

Explanation:

<u>Given the following data;</u>

Number of loops in primary coil, Np = 1 loop.

Number of loops in secondary coil, Ns = 8 loops

Voltage in secondary coil, Vs = 120V

To find the voltage in the primary coil, Vp;

Transformer ratio is given by the formula;

\frac{V_{p}}{V_{s}} = \frac{N_{p}}{N_{s}}

Making Vp the subject of formula;

V_{p} = \frac{N_{p}}{N_{s}} * V_{s}

Substituting into the equation, we have;

V_{p} = \frac{1}{8} * 120

V_{p} = \frac{120}{8}

V_{p} = 15 V

Therefore, the voltage in the primary coil, Vp is 15 Volts.

4 0
3 years ago
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